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ryzh [129]
3 years ago
12

John wrote 1/5 of a paper in 1/4 of an hour how long did it take him to write an entire paper?\

Mathematics
2 answers:
Helen [10]3 years ago
7 0

1 hour and 15 minutes. A quarter of an hour is 15 minutes. A full paper would be 5/5. So you would take 15x5 which would give you 75 minutes or an hour and 15 minutes

agasfer [191]3 years ago
6 0

Answer:

2 hours and 5 minutes.

Step-by-step explanation:

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piper needs to buy 320 new ping-pong balls for the team ping pong balls come in 16 how many sets of ping-pong balls should piper
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20 sets

Step-by-step explanation:

320/16=20

He needs 320 ping pong balls, and he has 16, so divide the amount needed by the amount that comes in each containter.

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I dont know what a complementary angle is, can someone help me with this quistion please?
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A, complementary angles sum up to 90°

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3 years ago
Steve picks 55 pounds of pears. He packs an equal amount of pears into 6 bags. He then has 4 pounds of pears left. What is the w
Serggg [28]
Because he has 4 pounds of apples left, you are to subtract that from the total pounds picked, which was a total of 55 pounds. So 55 with 4 taken away, or 55 - 4, equals 51. Since he had equally put 51 pounds into six bags, you are to then divide . 51 / 6 = 8.5. He had put 8.5 pounds worth of apples into each bag.
4 0
2 years ago
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2. For every orange there
baherus [9]

Answer:

The equivalent ratios are B and C.

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3 years ago
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Calculate the average travel time for each distance, and then use the results to calculate. A 6-column table with 3 rows in the
BigorU [14]

The average travel time is simply the mean travel time between the given points

  • The average time that it takes for the car to travel the first 0.25m is 2.23s.
  • The average time to travel just between 0.25m and 0.50m is 0.9s.
  • Given the time taken to travel the second 0.25 m section, the velocity would be 0.28m/s.

<u>(a) The average time to travel the first 0.25m</u>

The time travel in the first 0.25m are: 2.24s, 2.21s and 2.23s.

So, the average time to travel is:

Time = \frac{2.24s + 2.21s + 2.23s}{3}

Time = \frac{6.68s}{3}

Time = 2.23s

<u>(b) The average time to travel just between 0.25m and 0.50m</u>

The time travel in the 0.50m are: 3.16s, 3.08s and 3.15s.

So, the average time to travel this distance is:

Time = \frac{3.16s + 3.08s + 3.15s}{3}

Time = \frac{9.39s}{3}

Time = 3.13s

The average time to travel between both distance is the difference between the average time of each distance.

So, we have:

Average = 3.13s - 2.23s

Average = 0.9s

<u>(c) The velocity in the second 0.25m section</u>

The distance and time are:

Distance = 0.25m

Time = 0.9s

So, the velocity is:

Velocity = \frac{Distance}{Time}

This gives

Velocity = \frac{0.25m}{0.9s}

Velocity = 0.28m/s

Read more about distance, velocity and time at:

brainly.com/question/4931057

6 0
2 years ago
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