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4 years ago

11

A packing crate can hold 205 avocados.there were 7000 avocadospicked at a large grove. The owner has 36 packing crates. Does he

have enough crates to ship out the avocados

2 answers:

topjm [15]4 years ago

6 0

7000 ÷ 205 = <span>34.146.......

So the owner does have enough crates. In fact he will have some extra's in the end.

Hope I helped ya!!☺☺☺☺☺☺☺☺</span>

ale4655 [162]4 years ago

3 0

To solve this problem, you need to figure out whether or not the owner has enough crates to ship out all of the avocados.

To do this, first you need to find out how many avocados all of your crates can hold. To do this, you multiply the number of crates you have by the number of avocados each crate can hold. 36*205=7380.

Therefore, the owner can ship out up to 7380 avocados. He wants to ship 7000 avocados. 7000<7380.

So, yes, the owner has enough crates to ship out the avocados.

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Construct a quadratic polynomial whose zeroes are negatives of the zeroes of the

sp2606 [1]

Given:

The given quadratic polynomial is :

$x^2-x-12$

To find:

The quadratic polynomial whose zeroes are negatives of the zeroes of the given polynomial.

Solution:

We have,

$x^2-x-12$

Equate the polynomial with 0 to find the zeroes.

$x^2-x-12=0$

Splitting the middle term, we get

$x^2-4x+3x-12=0$

$x(x-4)+3(x-4)=0$

$(x+3)(x-4)=0$

$x=-3,4$

The zeroes of the given polynomial are -3 and 4.

The zeroes of a quadratic polynomial are negatives of the zeroes of the given polynomial. So, the zeroes of the required polynomial are 3 and -4.

A quadratic polynomial is defined as:

$x^2-(\text{Sum of zeroes})x+\text{Product of zeroes}$

$x^2-(3+(-4))x+(3)(-4)$

$x^2-(-1)x+(-12)$

$x^2+x-12$

Therefore, the required polynomial is $x^2+x-12$ .

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3 years ago

A room contains three urns: u1, u2, u3. u1 contains 3 red and 2 yellow marbles. u2 contains 3 red and 7 yellow marbles. u3 conta

Archy [21]

Answer:

$\dfrac{11}{30}$

Step-by-step explanation:

Urn U1: 3 red and 2 yellow marbles, in total 5 marbles.

The probability to select red marble is $\dfrac{3}{5}=0.6.$

Urn U2: 3 red and 7 yellow marbles, in total 10 marbles.

The probability to select red marble is $\dfrac{3}{10}=0.3.$

Urn U1: 1 red and 4 yellow marbles, in total 5 marbles.

The probability to select red marble is $\dfrac{1}{5}=0.2.$

The probability to choose each urn is the same and is equal to $\frac{1}{3}.$

Thus, the probability that the marble is red is

$\dfrac{1}{3}\cdot 0.6+\dfrac{1}{3}\cdot 0.3+\dfrac{1}{3}\cdot 0.2=\dfrac{1.1}{3}=\dfrac{11}{30}.$

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3 years ago

How do you work this out? need help asap

Svetlanka [38]

Hello,

Line 1 is passing through (-4,3), (-2,7) has a slope of (3-7)/(-4+2)=2

Line 2 is passing through (2,9), (4,1) has a slope of (9-1)/(2-4)=-4

One other way:

y=9-1/2 x²
y'=-x

gradient 1=-(-2)=2 for point (-2,7)

gradient 2=-(4)=-4 for point(4,1)

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3 years ago

Factor:14x3 – 21x

Vlada [557]

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3 years ago

The point R(-3,a,-1) is the midpoint of the line segment jointing the points P(1,2,b)

wlad13 [49]

Answer:

The values are:

$a = -5/2$

$b = -6$

$c = -7$

Step-by-step explanation:

Given:

P = (x₁, y₁, z₁) = (1, 2, b)

Q = (x₂, y₂, z₂) = (c, -7, 4)

m = R = (x, y, z) = (-3, a, -1)

To Determine:

a = ?

b = ?

c = ?

Determining the values of a, b, and c

Using the mid-point formula

$m\:=\:\left(\frac{x_1+x_2}{2},\:\frac{y_1+y_2}{2},\:\frac{z_1+z_2}{2}\right)$

As the point R(-3, a, -1) is the midpoint of the line segment jointing the points P(1,2,b) and Q(c,-7,4), so

m = R = (x, y, z) = (-3, a, -1)

Using the mid-point formula

$m\:=\:\left(\frac{x_1+x_2}{2},\:\frac{y_1+y_2}{2},\:\frac{z_1+z_2}{2}\right)$

given

(x₁, y₁, z₁) = (1, 2, b) = P

(x₂, y₂, z₂) = (c, -7, 4) = Q

m = (x, y, z) = (-3, a, -1) = R

substituting the value of (x₁, y₁, z₁) = (1, 2, b) = P, (x₂, y₂, z₂) = (c, -7, 4) = Q, and m = (x, y, z) = (-3, a, -1) = R in the mid-point formula

$m\:=\:\left(\frac{x_1+x_2}{2},\:\frac{y_1+y_2}{2},\:\frac{z_1+z_2}{2}\right)$

$\left(x,\:y,\:z\right)\:=\:\left(\frac{1+c}{2},\:\frac{2+\left(-7\right)}{2},\:\frac{b+4}{2}\right)$

as (x, y, z) = (-3, a, -1), so

$\left(-3,\:a,\:-1\right)\:=\:\left(\frac{1+c}{2},\:\frac{2+\left(-7\right)}{2},\:\frac{b+4}{2}\right)$

<u>Determining 'c'</u>

-3 = (1+c) / (2)

-3 × 2 = 1+c

$1+c = -6$

$c = -6 - 1$

$c = -7$

<u>Determining 'a'</u>

a = (2+(-7)) / 2

$2a = 2-7$

$2a = -5$

$a = -5/2$

<u>Determining 'b'</u>

-1 = (b+4) / 2

$-2 = b+4$

$b = -2-4$

$b = -6$

Therefore, the values are:

$a = -5/2$

$b = -6$

$c = -7$

6 0

3 years ago