There is some ambiguity here which could be removed by using parentheses. I'm going to assume that you actually meant:
x-3
h(x) = ---------------
(x^3-36x)
To determine the domain of this function, factor the denominator:
x^3 - 36x = x(x^2 - 36) = x(x-6)(x+6)
The given function h(x) is undefined when the denominator = 0, which happens at {-6, 0, 6}.
Thus, the domain is "the set of all real numbers not equal to -6, 0 or 6."
Symbolically, the domain is (-infinity, -6) ∪ (-6, 0) ∪ (0, 6) ∪ (6, +infinity).
Answer:
Forces in our Universe
Step-by-step explanation:
a)
First of all we have,

and,

We need to define a function that allows us to find said change based on r, so one of the functions that shows that change is,

That is,

For this case F is a conservative field and the line integral is independent of the path. Thus, defining
and
. So the amount of work on the movement of the object from P1 to P2 is,




2) The gravitational force field is given by,

The maximum distance from the earth to the sun is
km and the minimum distance is
km. The mass values of the bodies are given by m =
kg, M =
kg and the constant G is

In this way we raise the problem like this,




Answer:
The answer is 25
Step-by-step explanation:
Answer:
The length of A will be 8 as
The ratio between the sides are 4:1
Since Side is 2 therefore side A=2*4
=8
Hope u got your answer..
Answer:
Q.5 ab=cd
Q.6 ad=bc
Q.7 ce=ae
Q.8 eb=ed
Q.9 angle D=angle B (opposite angle of parallelogram are equal)
let other angle of parallelogram be x.
angle A+angle B +angle C + angle D= 360° (sum of quadrilateral is 360°)
x+130°+x+130°=360°
2x+260°=360°
2x=360°-260°
2x=100°
x=100/2
x=50°
Q.10 similarly, angle b= angle d
let other angle be x.
x+61°+ x+61°=360°
2x+122°=360°
2x=360°+122°
2x=238°
x=238°/2
x=119°
Q.11 in quadrilateral opposite angles are equal and opposite angle of parallelogram are equal.
Q.12 in quadrilateral opposite angle are equal and opposite angle of parallelogram are equal.
Q.13 in quadrilateral opposite sides are equal and opposite sides are parellel and this property is also present in parallelogram.
q.14 in quadrilateral diagonal bisected each other and diagonal of parallelogram also bisect each other.