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Tcecarenko [31]
3 years ago
5

Mark commutes to work on his bicycle

Mathematics
1 answer:
SpyIntel [72]3 years ago
6 0
Need more context please
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Simplify the expression:<br><br> –5(6 − 2y) =
Vadim26 [7]
-30+10y
hope this helps!
3 0
3 years ago
Read 2 more answers
PLEASE I REALLY NEED HELP!
vagabundo [1.1K]

Answer:

\frac{3}{28}

Step-by-step explanation:

Probability (P) is calculated as

P = \frac{requiredoutcome}{count}

The first required outcome is a red sweet from a total of 3 + 5 = 8

P( red) = \frac{3}{8}

There are now 2 red left and a count of 7, since 1 has been eaten, thus

P( second red ) = \frac{2}{7}

P( red and red ) = \frac{3}{8}  × \frac{2}{7} = \frac{6}{56} = \frac{3}{28}

6 0
3 years ago
PLEASE HELP!!!!!
Margaret [11]

Answer:

60°

Step-by-step explanation:

since all sides of a triangle are equal .The given triangle is an equilateral triangle. And each angles of an equilateral triangles is 60 degree.So angle A is also 60 degree.

5 0
3 years ago
Solve for U -8u = - 16/3
lorasvet [3.4K]

Answer:

u = 2/3

Step-by-step explanation:

Simply divide both sides by -8:

u = (-16/3)/-8

If you don't have a calc, use KCF:

u = (-16/3)(-1/8)

u = 16/24

u = 2/3

4 0
3 years ago
A population is known to be normally distributed with a standard deviation of 2.8. (a) Compute the 95% confidence interval on th
Ugo [173]

Answer:

Step-by-step explanation:

Mean = sum of terms/number of terms

The mean of the given sample is

(8 + 9 + 10 + 13 + 14 + 16 + 17 + 20 + 21)/9 = 14.2

a)

For a confidence level of 95%, the corresponding z value is 1.96.

We will apply the formula

Confidence interval

= mean ± z ×standard deviation/√n

Where

n represents the number of samples

It becomes

14.2 ± 1.96 × 2.8/√9

= 14.2 ± 1.96 × 0.933

= 14.2 ± 1.83

The lower end of the confidence interval is 12.37

The upper end of the confidence interval is 16.03

b)

For a confidence level of 99%, the corresponding z value is 2.58

We will apply the formula

Confidence interval

= mean ± z ×standard deviation/√n

Where

n represents the number of samples

It becomes

14.2 ± 2.58 × 2.8/√9

= 14.2 ± 2.58 × 0.933

= 14.2 ± 2.4

The lower end of the confidence interval is 11.8

The upper end of the confidence interval is 16.6

3 0
2 years ago
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