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alexira [117]
4 years ago
8

What is X^2 ÷ x^2+5x+6

Mathematics
1 answer:
Nata [24]4 years ago
3 0

Answer: Your Answer To This Problem Is  5x + 7 (:

Step-by-step explanation: x^2 / x^2 + 5x + 6 = 5x^3 + 7x^2 / X^2 = 5X + 7 (:

Hope I Helped!!!!!

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I need help asap :):);)
AysviL [449]
-4+2x>-4
2x>0
X> 0

The first answer.
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3 years ago
Drag the numbers to order them from greatest to least, with the greatest at the top.
Savatey [412]

10pi

9.92749....

square root of 101

0.99853....

6 0
3 years ago
Read 2 more answers
A local hamburger shop sold a combined total of 578 hamburgers and cheeseburgers on Tuesday. There were 72 fewer cheeseburgers s
andreev551 [17]
Let h be hamburgers and c be cheeseburgers.
We know that h + c = 578
We also know that c + 72 = h
This gives us a system of equations we can solve. My preferred method to solve systems is substitution, where we solve one equation for one of the variables, then substitute that solution in the other equation, reducing it to a single variable equation. One of the equations already equals h, so we can go straight into the sub part.
h + c = 578
(c + 72) + c = 578
c2 = 506
c = 253
Finally, we go back to the other equation and solve for h.
c + 72 = h
253 + 72 = h
325 = h
So, total there were 253 cheeseburgers sold, and 325 hamburgers sold.
6 0
4 years ago
Read 2 more answers
Can someone please help me on 8 and 13
STALIN [3.7K]

Answer:

i cant see the photo

Step-by-step explanation:

6 0
3 years ago
Consider the equivalence relation R = {( x, y) Ix-y is an integer}.
Vanyuwa [196]

Answer:

[1]=Z the set of integers

[1/2]={r/2| r is an odd integer}

Step-by-step explanation:

Denote by [a] the equivalence class of an element a.

We know that [a]={x|(x,a)∈R}. Then

[1]={x|(x,1)∈R}={x|x-1 is an integer}={x|x-1=k for some k∈Z}

={x|x=k+1 for some k∈Z}={k+1|k∈Z}={...,-2+1,-1+1,0+1,1+1,2+1,...}=Z

For the other class, we have

[1/2]={x|(x,1/2)∈R}={x|x-1/2 is an integer}={x|x-1/2=r for some r∈Z}

={x|x=r+1/2 for some r∈Z}={r+1/2|r∈Z}={...,-2+1/2,-1+1/2,0+1/2,1+1/2,..}

={...,-3/2,-1/2,1/2,3/2,...}={r/2| r is an odd integer}

6 0
3 years ago
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