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frutty [35]
3 years ago
13

A fish tank contains 16 goldfish and 24 guppies. If you randomly select 2 fish, what is the probability that they are both goldf

ish?
Mathematics
2 answers:
morpeh [17]3 years ago
4 0
Hello, Shakiya214!

If a fish tank contains 16 goldfish and 24 guppies, then we can deduce that the total number of fish in the tank is: 16 + 24 = 40 fish.
If there are 16 goldfish in the tank, then of the 40 total fish, we have a probability of 16/40.

To illustrate this idea, suppose we had n fish in the tank (a guppies and b goldfish). The probability of selecting any fish is 100% (because there are only fish in the tank). If we had to select the goldfish, we could choose them like this:

p₁, p₂, p₃, p₄ ... pₐ

We could choose any one of these fish twice. This leaves us with: 16/40
Now, if they were NOT replaced, we could simply do it again. Except this time, we can only choose 15 out of the remaining 39 goldfish, leaving us with a probability of: (16/40)(15/39) = 240/1560 = 6/39 = 2/13
liq [111]3 years ago
3 0
2/13 is the answer do 16*15 and 40*39 which equals 240 1560 find a number with the fraction and the answer comes out to 2/13
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Standard Form: 4.068
3 0
3 years ago
A batch of 400 containers for frozen orange juice contains 5 that are defective. Two are selected, at random, without replacemen
zavuch27 [327]

Answer:

0.0100250

0.0001566

0.0000009445555

Step-by-step explanation:

Given the following :

Total number of containers = 400

Number of defective oranges = 5

2 are randomly selected without replacement :

A.) What is the probability that the second one selected is defective given that the first one was defective?

Since selection is without replacement and given that the first pick is defective ; number of defective oranges left = 4 ; total oranges left in container = (400 - 1) = 399

Hence,

Probability = (required outcome / Total possible outcomes)

P(2nd defective given 1st is defective) = 4 / 399

27. What is the probability that both are acceptable?

This means probability that both picks aren't defective.

Ist pick = 1 - P(defective) = (1 - (395/400) = 0.0125

2nd pick = 1 - P(defective) 1 - (394/399) = 0.0125313

.Hence, 0.0125 × 0.0125313 = 0.0001566

28. If three are selected without replacement, what is the probability that all three are defective?

1st pick = 5 / 400 = 0.0125

2nd pick = 4 / 399 = 0.0100250

3rd pick = 3 / 398 = 0.0075376

Hence, (0.0125 × 0.0100250 × 0.0075376) = 0.0000009445555

5 0
3 years ago
Which graph represents exponential decay?
Reika [66]
Answer: the first graph


Reasoning: When a graph is going left to right it is a decay while when it’s going right to left it is an increase... think of linear equations where if it is going from left to right the slope is negative, it’s the same for the exponential decay and increase.
4 0
3 years ago
Read 2 more answers
Determine the intercepts of the line that passes through the following points. (-15,5) (-9,10) (-3,15)
notsponge [240]
To find the x and y-intercept, we can write an equation in slope intercept form. 
first, we need to find the slope
the formula for slope is 
m= (y₂-y₁)/(x₂-x₁)

now just put any two points into the equation
m=(10-5)/(-9-(-15)
m=5/6

so now we can write the slope-intercept equation
y=5/6x + b

in a slope-intercept equation, b is equal to the y-intercept, so we can take one of our 3 pairs of points and put them into the equation to solve for b

15= 5/6(-3) +b
15=-2.5 + b
17.5 = b
so now we know the y-intercept is (0,17.5)

now we can write the equation as 
y= 5/6x + 17.5

since the x intercept is when y=0, we can set y to 0 and then solve for x

0= 5/6x +17.5
-17.5 = 5/6x
-21 = x 

by setting y to zero, we figured out that the x-intercept is (-21,0)

hope this helped!

6 0
3 years ago
A six-sided number cube is rolled 300 times. The results are 120 even numbers and 180 odd numbers.
Stella [2.4K]

Answer:

What is the probability formula?

Image result

In general, the probability is the ratio of the number of favorable outcomes to the total outcomes in that sample space. It is expressed as, Probability of an event P(E) = (Number of favorable outcomes) ÷ (Sample space).

6 0
2 years ago
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