Question

Half of the smaller of two consecutive even integers is equal to two more than the larger integer. find both integers Please i will give brainliest ASAP

Answer 1

Answer:

-8 and -6.

Step-by-step explanation:

Let the first even integer be a.

Since the second is a consecutive even integer, it is given by (a + 2).

Half of the smaller (i.e. a) is equal to two more than the larger (i.e. a + 2). In other words:

$\displaystyle \frac{a}{2} = (a + 2) + 2$

Solve for a:

$\displaystyle \begin{aligned}\displaystyle \frac{a}{2} &= (a + 2) + 2\\ \\ \frac{a}{2} &= a + 4\\ \\ a &= 2a + 8 \\ \\ a &= -8 \end{aligned}$

In conclusion, the two even, consecutive integers are -8 and -6.