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IceJOKER [234]
3 years ago
15

What is the radius of the circle given by the equation below?

Mathematics
1 answer:
grandymaker [24]3 years ago
8 0
x^2+18x+y^2+18y=-146 \\ \\( x^2+18x + 81)+(y^2+18y+81)-81-81=-146\\ \\(x+9)^2+(y+9)^2=-146+81+81\\ \\(x+9)^2+(y+9)^2=-146+162\\ \\(x+9)^2+(y+9)^2=16
 
This \ is \ in \ the \ general \ circle \ form : (x-h)^ 2+ (y-k)^2 = r^2, so: \\ \\ r^2=16 \\ \\r=\sqrt{16}\\ \\r=4 \\ \\ Answer : \ C. 4


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Answer:

Graph A → Equation A → Table B → Property D

Graph D → Equation B → Table A → Property B

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Step-by-step explanation:

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