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IceJOKER [234]
3 years ago
15

What is the radius of the circle given by the equation below?

Mathematics
1 answer:
grandymaker [24]3 years ago
8 0
x^2+18x+y^2+18y=-146 \\ \\( x^2+18x + 81)+(y^2+18y+81)-81-81=-146\\ \\(x+9)^2+(y+9)^2=-146+81+81\\ \\(x+9)^2+(y+9)^2=-146+162\\ \\(x+9)^2+(y+9)^2=16
 
This \ is \ in \ the \ general \ circle \ form : (x-h)^ 2+ (y-k)^2 = r^2, so: \\ \\ r^2=16 \\ \\r=\sqrt{16}\\ \\r=4 \\ \\ Answer : \ C. 4


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The volume of the sphere with the given value of diameter is to the nearest tenth is 3052.1cm³.

Option C is the correct answer.

<h3>What is the volume of the sphere?</h3>

The volume of  the sphere is the amount of space occupied within the sphere.

Volume of sphere is expressed as;

V = (4/3)πr³

Where r is the radius and π is pi ( π = 3.14 )

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