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ozzi
4 years ago
15

Write a unit rate for the situation. Round to the nearest hundredth if necessary.

Mathematics
1 answer:
Ilya [14]4 years ago
8 0

Answer:

35.33 km/h.

Step-by-step explanation:

Given: Distance= 212 km.

           Times= 6 hours

Now, finding unit rate (speed) for the situation.

Formula; Speed= \frac{Distance}{time}

Speed (rate)= \frac{212}{6} = 35.3333\ km/h

Speed (rate)= 35.3333≅ 35.33 km/h (nearest hundredth).

∴ Rate of the unit is 35.33 km/h

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miss bella's mathematics class consists of 6 sophomores 12 juniors and 10 seniors how many different ways can miss bell create a
Aleks04 [339]

Answer:

792

Step-by-step explanation:

5 0
3 years ago
To prove that DEF congruent DGF by SAS,what additional information is needed
lisabon 2012 [21]

Answer:

∠DFE ≅ ∠DFG

Step-by-step explanation:

we know that

Triangles are congruent by SAS, if any pair of corresponding sides and their included angles are equal in both triangles

In this problem we have that

The pair of corresponding sides that are equal are

EF=GF  and DF (is the same side for both triangles)

The included angle are ∠DFE and ∠DFG

therefore

The additional information needed to prove that triangles DEF and DGF are congruent by SAS is that angles ∠DFE and ∠DFG are equal

so

∠DFE ≅ ∠DFG

8 0
4 years ago
Read 2 more answers
True or false (Picture provided)
Naya [18.7K]
<h2>Hello!</h2>

The answer is: True.

<h2>Why?</h2>

A counterexample is a way that we can prove that something is not true about a mathematical equation or expression, it's also considered as an exception to a rule.

So:

sec^{2}x-1=\frac{cosx}{cscx}\\\\tg^{2}x=\frac{cosx}{\frac{1}{sinx}}\\\\\frac{1-cos2x}{1+cos2x}=cosxsinx

Then, evaluating we have:

\frac{1-cos(2*45)}{1+cos(2*45)}=cos(45)*sin(45)\\\\\frac{1-0}{1+0}=\frac{\sqrt{2} }{2}*\frac{\sqrt{2}}{2}\\\\1=\frac{(\sqrt{2})^{2} }{4}\\\\1=\frac{2}{4}\\\\1=\frac{1}{2}

Hence, we can see that the equation is not fulfilled, so, 45° is a counterexample for sec^{2}x-1=\frac{cosx}{cscx} and the answer is true.

Have a nice day!

3 0
4 years ago
A company that builds homes advertises that by choosing from its upgrade options each of its new homes is available In 256 diffe
lutik1710 [3]

Solution:

Let number of upgrade options = p

Let total number of distinct variations in which 256 new homes is available = k

So, p × p× p.....k times = 256

⇒p^k= 256

256= 2  × 2 ×2 ×2 ×2 ×2 ×2 ×2= 2^6

256= 4  ×4  ×4  × 4=4^4

So,Either, number of upgrade options = 2 ,

Or , Number of upgrade options = 4

3 0
3 years ago
Solve by substitution 5x-y=5 and-4x 5y=17
andriy [413]
I think you r qrong no offense
6 0
3 years ago
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