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ioda
3 years ago
9

Jing- sheng made a scaled copy of the following rhombus. He used a scale factor greater than 1. What could be the side length of

the scaled copy of the rhombus? Choose 2 answers
A 1
B 4/3
C 5
D 7.3
E 5

Mathematics
2 answers:
S_A_V [24]3 years ago
6 0

Answer:

See below.

Step-by-step explanation:

You don't provide the original side length, but since the scale factor is greater than 1, all correct answers are lengths that are greater than the original side length.

Answer: choose any two numbers that are greater than the original length.

Anni [7]3 years ago
5 0

Answer:

D and E

Step-by-step explanation:

I hope this helps!

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4 years ago
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the density of a certain material is such that weighs 6900 grams for every 4.5 quarts of volume express this density in pounds p
dlinn [17]

Answer:

d=101.4\ \text{pounds}/\text{feet}^3

Step-by-step explanation:

Given that,

Mass of material, m = 6900 grams

Volume of the material, V = 4.5 quarts

We need to find the density in pounds per cubic foot

We know that,

1 pound = 453.59 grams

⇒ 6900 grams = 15.21 pounds

Also, 1 cubic foot = 29.92 quarts

4.5 quart = 0.15 feet³

Density = mass/volume

Or

d=\dfrac{15.21\ \text{pounds}}{0.15\ \text{feet}^3}\\\\d=101.4\ \text{pounds}/\text{feet}^3

Hence, the density of the material is 101.4\ \text{pounds}/\text{feet}^3

3 0
4 years ago
Tom grew eight tomato plants with four seeds packets. How many seed packets does Tom need to have a total of 16 tomato plants?
Dmitriy789 [7]

Answer:

8 seed packets

Step-by-step explanation:

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8 0
3 years ago
A school bus 3 times as long as 4 meters how many centimeters long is the bus
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What two numbers' sum=-4 and product=-2
n200080 [17]

Let <em>a</em> and <em>b</em> be the two numbers. Then

<em>a</em> + <em>b</em> = -4

<em>a b</em> = -2

Solve the second equation for <em>b</em> :

<em>b</em> = -2/<em>a</em>

Substitute this into the first equation:

<em>a</em> - 2/<em>a</em> = -4

Multiply both sides by <em>a</em> :

<em>a</em>² - 2 = -4<em>a</em>

Move 4<em>a</em> to the left side:

<em>a</em>² + 4<em>a</em> - 2 = 0

Use the quadratic formula to solve for <em>a</em> :

<em>a</em> = (-4 ± √(4² - 4(-2))) / 2

<em>a</em> = -2 ± √6

If <em>a</em> = -2 + √6, then

-2 + √6 + <em>b</em> = -4

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In the other case, we end up with the same numbers, but <em>a</em> and <em>b</em> are swapped.

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