Consider the equation:
Subtracting '4' from both the sides of the equation, we get as
Squaring on both the sides of the equation, we get
Subtracting '2' from both the sides of the equation, we get
x=14
Since, An extraneous solution is a solution that arises from the solving process that is not really a solution at all. But, in this equation x=14 is the solution of the given equation.
Hence, it is not an extraneous solution.
Answer:
The answer: The factors are (2x-9) and (x+6).
The Problem:
Factor
Step-by-step explanation:
So I'm going to do trial factors using the choices to aid me.
Factored form for this problem if it exist will be in the form:
.
In general this is what it would look like if we factored any quadratic in terms of (given the quadratic is not prime but technically you could factor even over the complex numbers).
Let's look at:
We want to choose such that when you multiply them you get 2. Well those would have to be 2 and 1.
we want to choose such that when you multiply them you get -54. Based on the choices we want to get with -9 and 6, or 9 and -6. We don't know the order we want to choose it in either.
For example which of these would work:
We are going to consider only the outer and inner of FOIL since we already know the first times the first is and the last times the last is
.
Let's test the first one:
Outer: 2x(9)=18x
Inner: -6(x)=-6x
------------------------ADD!
18x-6x=12x
The first choice did not give us the middle term 3x.
Trying the second one would give us the opposite since they are in the same form as previous just the + and - are switched.
Let's look at the third one:
Outer: 2x(6)=12x
Inner: -9(x)=-9x
--------------------------ADD!
12x-9x=3x
This is the winner.
The answer: The factors are (2x-9) and (x+6).