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3 years ago

Please help me it's the last question!!

Chemistry

1 answer:

ArbitrLikvidat [17]3 years ago

7 0

Its the straight segment C because its position is not going up or down, so it is not moving.

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Ba(oh)2 is a strong electrolyte. determine the concentration of each of the individual ions in a 0.750 m ba(oh)2 solution.

Sindrei [870]

The concentration of each of the individual ions in a 0750 M Ba(OH)2 solution is

[Ba2+] = 0.750 M

[OH-]= 1.50 M

<h3>calculation</h3>

write the equation for dissociation

that is Ba(OH)2 (s)→ Ba2+(aq) + 2OH-(aq)

by use of mole ratio of Ba(OH)2 : Ba2+ which is 1: 1 the concentration of Ba2+ is therefore= 0.750M

by use of mole ratio of Ba(OH)2 : OH- which is 1:2 the concentration of OH- =0.750 M x2/1=1.50 M

7 0

4 years ago

Calculate the concentration of a 35.24ml Ca(OH)₂ Solution If 28.35ml of 1.21m HNO3 is needed to tritate

olya-2409 [2.1K]

Answer:

Ca(PH)3

Explanation:

5 0

3 years ago

Calculate the reaction rate given the following:

klasskru [66]

Answer:

0.0123 M/s

Explanation:

4 0

3 years ago

Determine the ph of a 0. 35 m aqueous solution of CH3NH2 (methylamine). The kb of methylamine is?

guajiro [1.7K]

The pH of 0.35 M of CH₃NH₂ is 12.09 and the $k_b$ for methylamine is 4.4 x 10⁻⁴.

pHis the quantitative measure of acidity and basicity of an aqueous or other liquid solution. The scale range goes from 0 to 14. Water has a pH of 7 and is neutral in nature.

<h3>What is dissociation constant?</h3>

The dissociation constant is an equilibrium constant that describes the dissociation or ionization of a base or an acid

$k_a$ describes the dissociation of an acid

$k_b$ describes the dissociation of a base

For methylamine,

$CH_3NH_2 + H_2O\Leftrightarrow CH_3NH_3^+ + OH^-$

Initial concentration of methylamine = 0.35 M

Initial concentration of products = 0

Let, at equilibrium concentration of CH₃NH₂ = 0.35 - x

Then, concentration of CH₃NH₃⁺ and OH⁻ is x and x respectively

$k_b = \frac{[CH_3NH_3^+] [OH^-]}{[CH_3NH_2]}$

The dissociation constant for methylamine, $k_b$ = 4.4 x 10⁻⁴

$4.4 \times 10^-^4 = \frac{x.x}{0.35} \\x^{2} = 4.4 \times 10^-^4 \times 0.35\\x^{2} = 1.54 \times 10^-^4 \\$

$x =0.0124$

pOH = -log[OH] = -log(0.0124) = 1.91

pH + pOH = 14

pH = 14 - 1.91 = 12.09

Thus, the pH of methylamine is 12.09 and $k_b$ is 4.4 x 10⁻⁴

Learn more about pH:

brainly.com/question/172153

#SPJ4

7 0

2 years ago

How many atoms of Ca are present in 80.156 grams of Ca? (4 points) 1.2044 × 1024 2.4088 × 1024 4.8270 × 1025 1.9346 × 1027

Alika [10]

Answer: 1.2044 × 10^24

Explanation:

1 mole of calcium is 40 gram

Based on Avogadro's law:

1 mole of any substance has 6.02 x 10^23 atoms, also 1 mole of calcium is 40gram

So, 1 mole of calcium = 6.02 x 10^23 atoms

Also, 1 mole of calcium is 40gram

40 grams of calcium = 6.02 x 10^23 atoms

80.156 grams of calcium = Z atoms

To get the value of Z, cross multiply:

Z atoms x 40 grams = 6.02 x 10^23 atoms x 80.156 grams

40Z = 482.54 x 10^23

Z = (482.54 x 10^23/40)

Z = 12.06 x 10^23

Put result in standard form

Z = 1.206 x 10^24 atoms

Thus, 1.206 x 10^24 atoms of Ca are present in 80.156 grams of Ca

6 0

4 years ago

Read 2 more answers