Answer:
The CSI is wrong.
Explanation:
1. Find the volume of the pool
The formula for the volume of a cylinder is V = πr²h
.
D = 12 m; h = 10 m
r = D/2 = (12 m/2) = 6.0 m
V = πr²h = π × (6.0 m)² × 10 m = π × 36 m²× 10 m = 360π m³ = 1100 m³
= 1.1. × 10⁶ L
2. Calculate the moles of OH⁻
n = cV = 1.0 × 10⁻² mol·L⁻¹ × 1.3 × 10⁶ L = 11 000 mol of OH⁻
3. Calculate the moles of acetic acid needed for neutralization
HA + OH⁻ ⟶ A⁻ + H₂O
The molar ratio of is 1 mol HA:1 mol OH⁻, so you need 11 000 moL of acetic acid.
4. Calculate the actual moles of acetic acid
You have four 5 L jugs of acetic acid pH 2
.
Volume = 20 L
[H⁺] = 10⁻² mol·L⁻¹ = 0.01 mol·L⁻¹
(a) Set up an ICE table
HA + H₂O ⇌ A⁻ + H₃O⁺
I/mol·L⁻¹: c 0 0
I/mol·L⁻¹: - 0.01 +0.01 +0.01
I/mol·L⁻¹: c - 0.01 0.01 0.01
![K_{\text{a}} = \dfrac{\text{[A]}^{-}\text{[H$_{3}$O$^{+}$]}}{\text{[HA]}} = 1.76 \times 10^{-5}](https://tex.z-dn.net/?f=K_%7B%5Ctext%7Ba%7D%7D%20%3D%20%5Cdfrac%7B%5Ctext%7B%5BA%5D%7D%5E%7B-%7D%5Ctext%7B%5BH%24_%7B3%7D%24O%24%5E%7B%2B%7D%24%5D%7D%7D%7B%5Ctext%7B%5BHA%5D%7D%7D%20%20%3D%201.76%20%5Ctimes%2010%5E%7B-5%7D)
(b) Calculate the concentration of acetic acid
![\begin{array}{rcl}\dfrac{\text{[A]}^{-}\text{[H$_{3}$O$^{+}$]}}{\text{[HA]}}& = & 1.76 \times 10^{-5}\\\\\dfrac{0.01\times 0.01}{c}& = & 1.76 \times 10^{-5}\\\\1 \times 10^{-4} & = & 1.76 \times 10^{-5}c\\c & = & \dfrac{1 \times 10^{-4}}{1.76 \times 10^{-5}}\\\\ & = & \text{6 mol/L}\\\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7D%5Cdfrac%7B%5Ctext%7B%5BA%5D%7D%5E%7B-%7D%5Ctext%7B%5BH%24_%7B3%7D%24O%24%5E%7B%2B%7D%24%5D%7D%7D%7B%5Ctext%7B%5BHA%5D%7D%7D%26%20%3D%20%26%201.76%20%5Ctimes%2010%5E%7B-5%7D%5C%5C%5C%5C%5Cdfrac%7B0.01%5Ctimes%200.01%7D%7Bc%7D%26%20%3D%20%26%201.76%20%5Ctimes%2010%5E%7B-5%7D%5C%5C%5C%5C1%20%5Ctimes%2010%5E%7B-4%7D%20%26%20%3D%20%26%201.76%20%5Ctimes%2010%5E%7B-5%7Dc%5C%5Cc%20%26%20%3D%20%26%20%5Cdfrac%7B1%20%5Ctimes%2010%5E%7B-4%7D%7D%7B1.76%20%5Ctimes%2010%5E%7B-5%7D%7D%5C%5C%5C%5C%20%26%20%3D%20%26%20%5Ctext%7B6%20mol%2FL%7D%5C%5C%5Cend%7Barray%7D)
The concentration of the acetic acid is 6 mol·L⁻¹
(c) Calculate the moles of acetic acid

You have 100 mol of acetic acid.
The CSI is wrong.
You don't have enough acetic acid to neutralize the pool.