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AVprozaik [17]
3 years ago
9

What is the middle term and first term of (2x-4)2

Mathematics
1 answer:
Otrada [13]3 years ago
8 0

Answer:

First term: 4x

"Middle" term: -8

Step-by-step explanation:

2(2x-4) is the same thing as 4x-8.

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A sample of 12 radon detectors of a certain type was selected, and each was exposed to 100 pCI/L of radon. The resulting reading
valkas [14]

Answer:

Null hypothesis:\mu = 100  

Alternative hypothesis:\mu \neq 100  

t=\frac{98.375-100}{\frac{6.109}{\sqrt{12}}}=-0.921  

p_v =2*P(t_{11}  

Step-by-step explanation:

1) Data given and notation  

Data: 105.6, 90.9, 91.2, 96.9, 96.5, 91.3, 100.1, 105.0, 99.6, 107.7, 103.3, 92.4

We can calculate the sample mean and deviation for this data with the following formulas:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}

The results obtained are:

\bar X=98.375 represent the sample mean  

s=0.6.109 represent the sample standard deviation  

n=12 sample size  

\mu_o =100 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

2) State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal to 100pCL/L, the system of hypothesis are :  

Null hypothesis:\mu = 100  

Alternative hypothesis:\mu \neq 100  

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{98.375-100}{\frac{6.109}{\sqrt{12}}}=-0.921  

4) P-value  

First we need to find the degrees of freedom for the statistic given by:

df=n-1=12-1=11

Since is a two sided test the p value would given by:  

p_v =2*P(t_{11}  

5) Conclusion  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significant different from 100 at 5% of significance.  

3 0
3 years ago
Someone, please help me lol I'm small brain
Eddi Din [679]

Answer:

Measure of EF: 1.98

Measure of AB: 6.16

Measure of HI: 12.2

Step-by-step explanation:

Trick I learned that's very helpful when solving these problems: SOH (Sine, Opposite, Hypotenuse)- CAH (Cosine, Adjacent, Hypotenuse)- TOA (Tangent, Opposite, Adjacent)

MEASURE OF EF

you're starting with angle D which is 26 degrees. You have the measure of the Hypotenuse (DF) and you're trying to find the measure of EF (the segment opposite the angle) so you would use Sine

to do the equation, i'm going to use x in place of EF. 0.44 = sin(26)

Formula: sin(angle) = (opposite)/(hypotenuse)

Equation:

0.44 = x/4.5       <----------- multiply by 4.5 to get x by itself

4.5*0.44 = x       <---------- 4.5 times 0.44

1.98= x       <----------------answer

MEASURE OF AB

trying to find hypotenuse and you already have the adjacent angle so you would use cosine. Using y in place of AB. 0.616 = sin(52)

cos(angle) = (adjacent)/(hypotenuse)

cos(52) = 10/y      <------ divide by y

y*0.616 = 10       <------------ divide by 0.616

y = 10/0.616    <----------- next you'll divide 10 by 0.616

y = 6.16    <-----------answer

MEASURE OF HI

trying to find adjacent, already have opposite so you would use tangent. tan(42) = 0.90. using z in place of HI

tan(angle) = (opposite)/(adjacent)

tan(42) = 11/z   <------------ multiply z on both sides

z*0.90 = 11  <--------- divide by 0.90 to get z by itself

z = 11/0.90    <-------- divide 11 by 0.90

z = 12.2

4 0
2 years ago
Fill in the blanks using each of the numbers 0–7 exactly once, so that the percent, decimal, and fraction below are ordered from
Scrat [10]

Answer:

I don't know

Step-by-step explanation:

Theres not enough information in the question

6 0
2 years ago
We gave a national verbal proficiency test that has a mean score of 500 with a standard deviation of 75. What raw score would co
charle [14.2K]

Answer:

519

Step-by-step explanation:

Let's assume that the scores for the national verbal proficiency test follow a normal distribution.

Mean score (μ) = 500

Standard deviation (σ) = 75

According to a Z-score table, the score for the 60th percentile is roughly z = 0.253

For any score "x", the z-score is given by:

Z=\frac{X-\mu}{\sigma}

For z = 2.53:

0.253=\frac{X-500}{75}\\X=519

The raw score to the 60th percentile is 519.

4 0
3 years ago
Choose the most reasonable estimate of the volume of a box with
Katen [24]

Answer:

D. 125cm

Step-by-step explanation:

Round each number for an estimate so you get 5 x 5 x 5 = 125

4 0
2 years ago
Read 2 more answers
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