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kolbaska11 [484]
3 years ago
15

if the vertex of a parabola is (-4,6) and another point on the curve is (-3,14), what is the coefficient of the squared expressi

on in the parabola's equation?
Mathematics
1 answer:
Softa [21]3 years ago
3 0

Answer:

8

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (- 4, 6 ), thus

y = a(x + 4)² + 6

To find a substitute (- 3, 14) into the equation

14 = a(- 3 + 4)² + 6 ( subtract 6 from both sides )

8 = a

Thus the coefficient of the x² term is a = 8

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Answer:

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<em />

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3 years ago
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dale has a square garden. He adds a 2-foot-wide walkway around his garden. If the total area of the walkway and garden is 196 sq
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Let the side of the garden alone (without walkway) be x.  
Then the area of the garden alone is x^2.  
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(x-10(x+18) = 0

x=10 or x=-18.  We must discard x=-18, since the side length can't be negative.  We are left with x = 10 feet.

The garden dimensions are (10 feet)^2, or 100 square feet.


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3 years ago
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