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kolbaska11 [484]
3 years ago
15

if the vertex of a parabola is (-4,6) and another point on the curve is (-3,14), what is the coefficient of the squared expressi

on in the parabola's equation?
Mathematics
1 answer:
Softa [21]3 years ago
3 0

Answer:

8

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (- 4, 6 ), thus

y = a(x + 4)² + 6

To find a substitute (- 3, 14) into the equation

14 = a(- 3 + 4)² + 6 ( subtract 6 from both sides )

8 = a

Thus the coefficient of the x² term is a = 8

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Goryan [66]
The correct answer is A
5 0
4 years ago
Factorise 4x^2-y^2 please help
kotegsom [21]

Answer:

(2x + y)(2x - y)

Step-by-step explanation:

1. Simplify the square 4x²:

(2x)² - y²

2. Apple the difference of two squares formula <em>x² - y² = (x + y)(x - y)</em>:

(2x + y)(2x - y)

hope this helps!

8 0
2 years ago
Find the value of x.<br> 17<br> X-4
kipiarov [429]

Answer:

x = 12.5

Step-by-step explanation:

17 = 2(x - 4)

17 = 2x - 8

17 + 8 = 2x - 8 + 8

25 = 2x

12.5 = x

7 0
3 years ago
Help, algebra 1, thanks plzz
RideAnS [48]

Answer:

9)  x = gy/c,   11) a = np/m

Step-by-step explanation:

9)  g = xc/y

   g*y/c = xc/y *y/c

   gy/c = x

11) am = np

    am/m = np/m

    a = np/m

6 0
3 years ago
How would I solve for 35?
svet-max [94.6K]
First you simplify both sides

Multiply -1 by x and 7
-x-7-16=x-3
Subtract -16 from -7
-x+9=x-3
Add 3. To both sides
-x+12=x
Add x to both sides
12=2x
Divide both sides by 2
6=x
8 0
3 years ago
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