The sum of the 8 terms of the series 1-1-3-5- ... -13 is -48
The given sequence is:
1,-1,-3, . . -13
and there are 8 terms.
The related series of this sequence is:
1-1-3-5- ... -13
Notice that the series is an arithmetic series with:
first term, a(1) = 1
common difference, d = -1 - (1) = -2
last term, a(8) = -13
To find the sum of the series, use the sum formula:
S(n) = n/2 [(a(1) + a(n)]
Substitute n = 8, a(1) = 1, a(n) = a(8) = -13 into the formula:
S(8) = 8/2 [1 + (-13)]
S(9) = 4 . (-12) = -48
Learn more about sum of a series here:
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Answer:
Now, each student contributes= Rs 61 1/2= Rs 123/2 ( mixed fraction ).
Therefore, total no. of students=Rs (1953/2÷123/2) = 15.87
Rounding off 15.87 to 16.
There were 16 students
(i hope it is correct answer. pls mark as brainliest)
What is it that I am supposed to be doing?
Answer:
12 cups of sugar
Step-by-step explanation:
i hope it right
