x-7> -9
x> -2 (add seven to nine)
See the attachment. Hope it will help you.
<em>Greetings from Brasil...</em>
Here we will apply rule of 3...
This formula, A = πR², its for the whole circle, that is, 360° (2π)
We want the area of only a part, that is, a circular sector whose angle π/6
sector area
2π ----- πR²
π/6 ----- X
2πX = (π/6).πR²
2πX = π²R²/6
X = π²R²/12π
<h3>X = πR²/12</h3>
If Ronisha multiply the area by 1/12 she will get the area of sector with angle of π/6
Answer:
Let the fraction be qp
So q=p+7
q−6p+17=2
⇒p+7−6p+17=2
⇒p+1p+17=2
⇒p+17=2p+2
⇒p=15
q=15+7=22
So qp=2215.
Step-by-step explanation:
hope it helps you please mark me as brainlist
Answer: I cant really read the questions.
Step-by-step explanation: