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Anika [276]
4 years ago
9

Select all possible solutions for 2x+7<=3x-5

Mathematics
2 answers:
ss7ja [257]4 years ago
7 0

12 is the solution. I couldn't find any others!

Ymorist [56]4 years ago
3 0

Answer:

12, 18, 24, 107

Step-by-step explanation:

Our inequality is

2x+7 ≤ 3x-5

First we will subtract 3x from each side:

2x+7-3x ≤ 3x-5-3x

-1x+7 ≤ -5

Subtract 7 from each side:

-1x+7-7 ≤ -5-7

-1x ≤ -12

Divide both sides by -1:

-1x/-1 ≤ -12/-1

When we multiply or divide an inequality by a negative number, we flip the inequality symbol:

x ≥ 12

We want numbers that are equal to or larger than 12; this leaves us with

12, 18, 24, and 107.

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The ratio of children to teachers at preschool is 14:5. How many children are at the preschool if there are 30 teachers
elena55 [62]

If the ratio is 14 childen to every 5 teachers, and there are thirty teachers... there are 84 children. hope I could help!

6 0
3 years ago
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Sally divided her 48 spools of thread evenly into six boxes. How many spools of thread did she put into each box?
lidiya [134]

Answer:

8 spools

Step-by-step explanation:

48 divided by 6

8 0
3 years ago
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If a polynomial function f(x) has roots –8, 1, and 6i, what must also be a root of f(x)? A. –6
anyanavicka [17]

Answer:

-6i

Step-by-step explanation:

Complex roots always come in pairs, and those pairs are made up of a positive and a negative version. If 6i is a root, then its negative value, -6i, is also a root.

If you want to know the reasoning, it's along these lines: to even get a complex/imaginary root, we take the square root of a negative value. When you take the square root of any value, your answer is always "plus or minus" whatever the value is. The same thing holds for complex roots. In this case, the polynomial function likely factored to f(x) = (x+8)(x-1)(x^2+36). To solve that equation, you set every factor equal to zero and solve for the x's.

x + 8 = 0

x = -8

x - 1 = 0

x = 1

x^2 + 36 = 0

x^2 = -36 ... take the square root of both sides to get x alone

x = √-36 ... square root of an imaginary number produces the usual square root and an "i"

x = ±6i

6 0
3 years ago
Read 2 more answers
For each function below, determine whether or not the function is injective and whether or not the function is surjective. (You
Harlamova29_29 [7]

Answer: First, injective means that for every y, there is only one x such f(x) = y, and surjective means that if f is a function that goes from the set {x} to the set {y}, for every element y in the codomain there is at least one element x in the domain such f(x) = y

(a) f:R----> + R given by f(x) = x2 (i guess you written x^{2})

The function is not injective, because f(-2) = f(2), and is surjective, because the codomain is +R, and x^{2} is always a positive real number.

(b) f:N----> + N given by f(n) = n2  (i guess you written n^{2})

As the naturals have no negative numbers, in this case the function is injective, but isn't surjective, because there is no number that when squared is equal to 5, for example.

(c) f: Zx Z → Z given by f(n, k) = n +k:

here the domain is of the form (n,k) and the function is n +k, so the numbers (z,w) and (w,z) return the same value when evaluated in f, then f is not injective. And is easy to see that f is surjective, because in the sum you can reach al the integers on the codomain.

3 0
3 years ago
Savannah had 400 chocolate chips. She saved x chips for a garnish, and mixed the rest of the chocolate chips evenly into 3 pans
goldfiish [28.3K]

Answer:

( 400-x)/3

Step-by-step explanation:

Total chocolate chips Savannah had = 400

Number of chocolate chips she saved for garnishing =x

Number of chocolate chips remain = 400-x

Number of brownie pans = 3

Chocolate chips were spread evenly in 3 pans,

Chocolate chips were in each pan of brownies =( 400-x)/3

5 0
3 years ago
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