Answer:
y = x² + 3x - 40
Step-by-step explanation:
Given the zeros are x = - 8 and x = 5, then the factors are
(x + 8) and (x - 5) and
y = (x + 8)(x - 5) ← expand factors
y = x² - 5x + 8x - 40, hence
y = x² + 3x - 40 ← in standard form
So what we have to do to solve this problem is to write down those values in 2 equations (one that represents what you sold and the other what your friend sold) compare them and find how much each ticket is worth.
First equation : 11x + 8y = 158
Where x = how much each adult ticket is
and y = how much each student ticket is
The second equation is : 5x + 17y = 152
Using the method of substitution , we can compare each equation side by side:
11x + 8y = 158
5x + 17y = 152
Now we need to set one of the variables of both equations so they are equal:
11(5)x + 8(5) = 158(5)
5(11)x + 17(11)x = 152(11)
55x + 40y = 790
55x + 187y = 1672
Then we subtract the second equation by the first one
55x-55x + 187y - 40y = 1672 - 790
147y = 882
y = 6
The we apply y to one of the equations to discover x :
11x + 8y = 158
11x + 8(6) = 158
11x + 48 = 158
11x = 110
x = 10
So the awnser is :
Each adult ticket (x) is $10
And each student ticket (y) is $8
I hope you understood my explanation,
Answer: Number 1= 2
Number 2= 55
Step-by-step explanation:
1. 16 divided by 4 is 4, 4-2=2
2. 22 divided by 2 is 11, 15 divided by 3 is 5, 11x5=55
Answer:
4n^2 + 22n
Step-by-step explanation:
10(n^2+n) -6 (n^2 - 2)
10n^2 + 10n - 6n^2 + 12
4n^2 + 22n
The sequence is an geometric progression;
Nth=a₁r^(n-1)
a₁ is the first term=-1
r=ratio=a₂/a₁=6/-1=-6
Nth=-1(-6^(n-1)
NTh=an
a₁=-1(-6⁰)=-1
a₂=-1(-6¹)=6
a₃=-1(-6²)=-36
a₄=-1(-6³)=216
therefore this serie is rising at an increasing fast speed, it is an geometric progression.
