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Salsk061 [2.6K]
2 years ago
5

A catering company charges $300 plus $40 per guest for a wedding. Sarah and Eric do not want to spend more than $5,000 on cateri

ng. Write and solve an inequality in terms of the number of guests, g, that can be invited. A) 300 - 40g ≥ 5000; g ≥ 117 B) 300 - 40g ≤ 5000; g ≤ 118 C) 300 + 40g ≤ 5000; g ≤ 117 D) 300 + 40g ≤ 5000; g ≤ 118
Mathematics
2 answers:
Fynjy0 [20]2 years ago
8 0
Your answer would be either c or d
marta [7]2 years ago
5 0
<span> 300 + 40g ≤ 5000; g ≤ 118</span>
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Use the Distributive Property to multiply.) -4x(x - 7)*
ad-work [718]

Answer:

-4x^2-28x

Step-by-step explanation:

Distribute

-4x(x) and -4x(-7)

-4x^2 and -28x

5 0
3 years ago
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Can someone help me round up decimals plzz
boyakko [2]
In this situation, 0.782 would be rounded to 0.8

how to round a decimal: take the underlined number and look to the number located to the RIGHT of the underlined number, if the number to the right of the underlined number is 4 or less you leave the underlined number as is - but if the number right to underlined number is 5 or greater you round the underlined number up by one

ex. 1.83 [round to the nearest tenth]

answer: 1.80

instead of keeping the 3 [hundredth] you turn it into a 0.

3 0
3 years ago
evaluate the line integral ∫cf⋅dr, where f(x,y,z)=5xi−yj+zk and c is given by the vector function r(t)=⟨sint,cost,t⟩, 0≤t≤3π/2.
meriva

We have

\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} \vec f(\vec r(t)) \cdot \dfrac{d\vec r}{dt} \, dt

and

\vec f(\vec r(t)) = 5\sin(t) \, \vec\imath - \cos(t) \, \vec\jmath + t \, \vec k

\vec r(t) = \sin(t)\,\vec\imath + \cos(t)\,\vec\jmath + t\,\vec k \implies \dfrac{d\vec r}{dt} = \cos(t) \, \vec\imath - \sin(t) \, \vec\jmath + \vec k

so the line integral is equilvalent to

\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} (5\sin(t) \cos(t) + \sin(t)\cos(t) + t) \, dt

\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} (6\sin(t) \cos(t) + t) \, dt

\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} (3\sin(2t) + t) \, dt

\displaystyle \int_C \vec f \cdot d\vec r = \left(-\frac32 \cos(2t) + \frac12 t^2\right) \bigg_0^{\frac{3\pi}2}

\displaystyle \int_C \vec f \cdot d\vec r = \left(\frac32 + \frac{9\pi^2}8\right) - \left(-\frac32\right) = \boxed{3 + \frac{9\pi^2}8}

7 0
2 years ago
What is the slope of the line that passes through the points (5,3) and (-4,1)​
wariber [46]

Answer:

\frac{2}{9}

Step-by-step explanation:

Formula to find the slope:\frac{y_{2}-y_1}{x_2-x_1}

Notice it doesn't matter for which point being y2/x2 or y1/x1.

Just to make our life easier, I choose (5,3) as our second point and (-4,1) as our first point.

\frac{3-1}{5-(-4)}

=\frac{2}{9}

5 0
3 years ago
PLEASE HELPPP !!!!!!!!!!!
Bas_tet [7]

Answer:

42

Step-by-step explanation:

7 0
2 years ago
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