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Salsk061 [2.6K]
3 years ago
5

A catering company charges $300 plus $40 per guest for a wedding. Sarah and Eric do not want to spend more than $5,000 on cateri

ng. Write and solve an inequality in terms of the number of guests, g, that can be invited. A) 300 - 40g ≥ 5000; g ≥ 117 B) 300 - 40g ≤ 5000; g ≤ 118 C) 300 + 40g ≤ 5000; g ≤ 117 D) 300 + 40g ≤ 5000; g ≤ 118
Mathematics
2 answers:
Fynjy0 [20]3 years ago
8 0
Your answer would be either c or d
marta [7]3 years ago
5 0
<span> 300 + 40g ≤ 5000; g ≤ 118</span>
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Part B:
Andrew [12]

Articles of clothing that the store received last Thursday is 84

<u>Solution:</u>

Given that  

A clothing donation store received numerous articles of clothing on Thursday of last week.

The number of articles of clothing that the store received last Thursday is represented by the following expression:

4 (3x − 1) − 2 (6 + 2x)

Need to calculate articles of clothing that the store received last Thursday when x = 12.5

As on Thursday x = 12.5, need to substitute x = 12.5 in above equation to get number of articles received on Thursday.

On substituting x = 12.5, we get

4 ( (3 x 12.5 ) – 1 ) – 2 ( 6 + ( 2 x 12.5 ) )

=> 4 (37.5 – 1) – 2 (6 + 25)

=> 146 – 62 = 84

On substituting x = 12.5 , we are getting value of expression as 84.

Hence articles of clothing that the store received last Thursday is 84

3 0
3 years ago
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