Answer:
Rider 1 does one round in 15 min, and will complete another in each consecutive multiple of 15 min
Rider 2 does one round in 18 min, and will complete another in each consecutive multiple of 18 min
Assuming that they start together, they will complete another round together in a time that is both multiples of 15min and 18 min.
Then we need to find the smallest common multiple between 15 and 18.
To smallest common multiple between two numbers, a and b, is equal to:
a*b/(greatest common factor between a and b).
Now, the greatest common factor between 15 and 18 can be found if we write those numbers as a product of prime numbers, such as:
15 = 3*5
18 = 2*3*3
The greatest common factor is 3.
Then the smallest common multiple will be:
(15*18)/3 = 90
This means that after 90 mins, they will meet again at the starting place.
First we find the slope between the two given points.
m = (y2 - y1)/(x2 - x1) = (-5 - 2)/(7 - 6) = -7/1 = -7
Now we use the slope-intercept equation of a line.
y = mx + b
We use one point as x and y, and we solve for b.
2 = -7(6) + b
2 = -42 + b
b = 44
The equation is
y = -7x + 44
Answer: f(x) = -7x + 44
It would take 15 weeks and they would meet at 178lbs.
Answer:
45-13= 32
32/8= 4
she can buy 4 lbs ham
Step-by-step explanation:
Answer:
false
Step-by-step explanation:
