3 years ago

Can you please help me with 7,8, and 9 :)

1 answer:

5 0

$x^2+7x=-12\\x^2+7x+12=0\\x^2+3x+4x+12=0\\x(x+3)+4(x+3)=0\\(x+4)(x+3)=0\\x=-4\ and \ x=-3$

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maxonik [38]

Answer:

Step-by-step explanation:

Δ AQP and Δ ACB are similar triangles, thus the ratios of corresponding sides are equal, that is

$\frac{AQ}{AC}$ = $\frac{PQ}{BC}$ ( note that AC = 3 + 6 = 9 ), substitute values

$\frac{3}{9}$ = $\frac{4.5}{BC}$ ( cross- multiply )

3BC = 40.5 ( divide both sides by 3 )

BC = 13,5 cm → C

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kari74 [83]

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saul85 [17]

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drek231 [11]

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Paladinen [302]

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