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evablogger [386]
3 years ago
11

Could any one explain this problem?

Mathematics
1 answer:
maxonik [38]3 years ago
8 0

Answer:

C

Step-by-step explanation:

Δ AQP and Δ ACB are similar triangles, thus the ratios of corresponding sides are equal, that is

\frac{AQ}{AC} = \frac{PQ}{BC} ( note that AC = 3 + 6 = 9 ), substitute values

\frac{3}{9} = \frac{4.5}{BC} ( cross- multiply )

3BC = 40.5 ( divide both sides by 3 )

BC = 13,5 cm → C

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Snape has 2000 mL of a magic potion solution that is 30% DeMuggle Juice. He also has hundreds of 25 mL bottles that are full of
ELEN [110]

Answer:

8

Step-by-step explanation:

We use the equation for the percentage of solute concentration in a solution:

volume percent = \frac{volume of solute}{volume of solution} * 100   (1)

In this case the equiation (1) is transformed into:

34 = \frac{Total volume of DeMuggle juice}{Total volume of the magic potion} * 100   (2)

n = number of times he must waves his wand to have a solution that is at least 34% DeMuggle juice.

Vpo = Initial volume of the magic potion = 2000ml

Vjo= Initial volume of DeMuggle juice = 30% * Vpo = (0.3)2000 = 600ml

Vb= Volume of a bottle = 25ml

Vjb = DeMuggle juice volume in a bottle = 75% * Vb = (0.75)25= 18.75ml

Vpmt = Total volume of the magic potion = 2000 + 25*n = Vpo + Vb * n

Vjt = Total volume of DeMuggle juice = 600 + 18.75*n = Vjo + Vjb * n

Replacing in (2):

34 = \frac{600 + 18.75*n }{2000 + 25*n} *100

\frac{34}{100} (2000 + 25*n) = (600 + 18.75* n)

680+8.5*n=600+18.75*n

80 = 10.25*n

n = 7.8

Since the number of times the wand should be waved must be an integer, it approximates 8

Replacing n=8 in (1)

\frac{600+(18.75*8)}{2000+(25*8)} *100 = 34.0909

6 0
4 years ago
25.5 is what percent of 60
OLEGan [10]
%/100 = is/of 
25.5%/100= x/60
The answer is 15.3

6 0
4 years ago
Read 2 more answers
The answers are not right and there not answering quickly there taking a long time to answer the question please what is the ans
Drupady [299]

Step-by-step explanation:

the volume is 4/3 × pi × r^3

4/3 × 3 × 4^3

the volume is 256 cm cubed.

the radius is 4 cm.

4 0
2 years ago
Suppose that the speed at which cars go on the freeway is normally distributed with mean 68 mph and standard deviation 5 miles p
denis23 [38]

Answer:

A)X \sim N(68 , 25)

B) the probability that is traveling more than 70 mph is 0.3446

C) the probability that it is traveling between 65 and 75 mph is 0.6449

D) 90% of all cars travel at least 56.85 mph fast on the freeway

Step-by-step explanation:

The speed at which cars go on the freeway is normally distributed with mean 68 mph and standard deviation 5 miles per hour.

Mean = \mu = 68 mph

Standard deviation = \sigma = 5 mph

A) X ~ N( _____, _______ )

In general X \sim N( \mu , \sigma^2)

\mu = 68 mph

\sigma = 5 mph

\sigma^2 = 5^2 = 25

So, X \sim N(68 , 25)

B) If one car is randomly chosen, find the probability that is traveling more than 70 mph.i.e.P(X>70)

So,Z = \frac{x-\mu}{\sigma}\\Z=\frac{70-68}{5}

Z=0.4

Using Z table

P(Z>70)=1-P(Z<70)=1-0.6554=0.3446

Hence the probability that is traveling more than 70 mph is 0.3446

C) If one of the cars is randomly chosen, find the probability that it is traveling between 65 and 75 mph.

P(65<X<75)

Z = \frac{x-\mu}{\sigma}

AT x = 65

Z=\frac{65-68}{5}

Z=-0.6

AT x = 75

Z=\frac{75-68}{5}

Z=1.4

Using Z table

P(65<X<75)=P(-0.6<Z<1.4)=P(Z<1.4)-P(Z<-0.6)=0.9192-0.2743=0.6449

Hence the probability that it is traveling between 65 and 75 mph is 0.6449

D)90% of all cars travel at least how fast on the freeway?

Since we are supposed to find at least how fast on the freeway

So,P(X>x)=0.9

1-P(X<x)=0.9

1-0.9=P(X<x)

0.1=P(X<x)

Z value at 10% =-2.23

So, Z=\frac{x-\mu}{\sigma}\\-2.23=\frac{x-68}{5}\\-2.23 \times 5 =x-68\\(-2.23 \times 5)+68=x

56.85 = x

Hence 90% of all cars travel at least 56.85 mph fast on the freeway

8 0
3 years ago
the length of a rectangle is 3 meters less than meters less than twice it’s width. write an equation to find the length of the r
Allisa [31]

x - 3 = 2y \\ \\
3 0
3 years ago
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