For the function h(x) = 2cot(x/2) an expression for the value of all asymptotes is

Given that (7, -6) is on the graph of f(x) , find the corresponding point for the function f(x+2)

ivolga24 [154]

<h3>Answer: (5, -6)</h3>

The point (7,-6) means x = 7 and y = -6 pair up. Recall that y = f(x). So if y = -6, then f(x) = -6 as well when x = 7. So f(7) = -6

Compare f(7) with f(x+2). We see that x+2 = 7 must be true. Isolate x by subtracting 2 from both sides

x+2 = 7

x+2-2 = 7-2

x = 5

The new x coordinate is x = 5. The y coordinate stays the same.

If we were to plug x = 5 into f(x+2), we would get

f(x+2) = f(5+2) = f(7) = -6

The input x = 5 leads to the output f(x+2) = -6

Visually, the point (7,-6) has been shifted 2 units to the left to land on (5,-6)

6 0

3 years ago

Which models best illustrates the inequality and its graph?

telo118 [61]

B. Tin can type at least 60 words per minute

Because on too it shows t > 60 but with the underline with it. The underline means equal so therefore its B.

6 0

3 years ago

11. What is the location of the vertex of the parabola defined by f(x) = −3x2 − 18x − 35 and in what direction does the parabola

lbvjy [14]

11. The given parabola has equation: $f(x)=-3x^2-18x-35$

We complete the square to have the function in the vertex form: $f(x)=-3(x^2+6x)-35$

$f(x)=-3(x^2+6x+9)+3*9-35$

$f(x)=-3(x^2+6x+9)+27-35$

$f(x)=-3(x+3)^2-8$

The vertex is (-3,-8), the graph opens down because a=-3<0

Ans: B. Vertex: (−3, −8), opens downward

12. We know the graph of $y=x^2$ is a parabola that opens up and has its minimum point at the origin.

The range of this function is $y\ge 0$

A straight line that has its y-intercept below the x-axis (y=3x-6) will not intersect $y=x^2$ and hence will form a system with no solution.

Ans: D. y equals x squared, y equals 3x minus 6

14. We want to find the zeros of $x^2+21x=5x-63$

$x^2+21x-5x+63=0$

$x^2+16x+63=0$

The factored form is $(x+7)(x+9)=0$

$x=-7\:or\: x=-9$

Ans: C. x = −7, −9

15. The given quadratic expression is $6x^2-17x+10$

We split the middle term to obtain:

$6x^2-12x-5x+10=0$

We factor by grouping to get:

$6x(x-2)-5(x-2)=0$

$(x-2)(6x-5)=0$

Ans: D. 6x − 5

8 0

4 years ago

Read 2 more answers

A car traveling at 22.4 m/s skids to a stop in 2.55 s. Determine the skidding distance of

Marta_Voda [28]

Answer:

57.12 m

Step-by-step explanation:

velocity= distance/time

distance= velocity×time

=22.4×2.55

=57.12 m

7 0

3 years ago

Suppose we have samples of five men and of five women and have conducted a randomization test to compare the sexes on the variab

Annette [7]

Answer and Step-by-step explanation:

The data represent sample of five men and five women conducted a randomization test to compare the sexes on the variable pulse.

The samples revealed that in 120 out of 252 possible outcomes under randomization have large difference. From this information it cannot be concluded that the sexes differ with regard to pulse.

The hypothesis test should be conducted between treatment and response for valid conclusion. The student can consider the biological content of men and women or verbal statements. The answer varies from person to person according to their respective data set. Therefore, it cannot be concluded that the sexes differ with regard to pulse.

6 0

3 years ago