Answer:
a) <em>t</em> ≥ 5
b) (see below)
Step-by-step explanation:
First, make note of the info you are given and what you're trying to do:
- at midnight, 5°C
- drops consistently 2°C per hour
- finding <em>t</em>
- <em>t </em>= # of hours past midnight when temp. was past -4°C
- put <em>t</em> on a number line
So, first, you need to find the first point at when the temperature goes past -4°C. Notice that the question is asking for past -4°C, not -4°C<em> and</em> past. This means we're not including -4°C.
Every hour, we're dropping by 2°C. You can draw a visual to better understand the situation. See the image below.
So we know that starting from 5 am, we are lower than -4°C.
This is 5 hours from midnight.
So <em>t</em> ≥ 5. This means that the number of hours past midnight when the temperature was colder than -4°C was 5 or more hours.
On the number line, draw a circle on 5 (between 4 and 6), but shade it in because it includes 5. Then, shade or highlight to the right of that circle to the end of the number line.
This shows that <em>t</em> is equal to or greater than 5.
Answer:
Step-by-step explanation:
a) Complete the table
Monday Tuesday Wednesday Total
Female 21-14=7 38-13-7= 18 13 38
Male 14 33-18= 15 26-13 =13 80-38=42
Total 80-33-26= 21 33 26 80
b) P(the student is a female) = 38/80= 0.475
c) P(the student visited the library on Tuesday) = 33/80= 0.4125
If x+y=5, let y = 0 to find the x-intercept: x=5. The x-int. is at (5,0).
Let x = 0 to find the y-int: y=5. The y-int is (0,5).
Plot (5,0) and (0,5), and then draw a straight line thru both points.
If x+y=5, solving for y results in y = -1x + 5
Comparing this to y = mx + b, m=-1 and b= 5. Again, the y-int. is (0,5).