Select all statements that are true about the linear equation. y=12x−4y=12x-4 The graph of the equation is the set of all points
that are solutions to the equation. The point (−6,7)(−6,7) is on the graph of the equation. The graph of the equation is a single point representing one solution to the equation. The point (−4,−6)(−4,−6) is on the graph of the equation.
2 answers:
Answer:
<h2>The graph of the equation is the set of all points that are solutions to the equation.</h2>Step-by-step explanation:
The given equation is
The true statement is the first one, because the graph of an equation always represent all points that are solutions. That is, all solutions for this equation are all the points placed on the line. The graph of the given linear equation is attached.
You can see in the graph that the points (-6,7) and (-4,-6) are not solutions for this equation, because they aren't on the line.
Also, you can see that the equation represents an infinite line, that is, the equation doesn't have a single solution.
Therefore, the true statement is the first one.
You might be interested in
We have that
A(-2,-4) B(8,1) <span>
let
M-------> </span><span>the coordinate that divides the directed line segment from A to B in the ratio of 2 to 3
we know that
A--------------M----------------------B
2 3
distance AM is equal to (2/5) AB
</span>distance MB is equal to (3/5) AB
<span>so
step 1
find the x coordinate of point M
Mx=Ax+(2/5)*dABx
where
Mx is the x coordinate of point M
Ax is the x coordinate of point A
dABx is the distance AB in the x coordinate
Ax=-2
dABx=(8+2)=10
</span>Mx=-2+(2/5)*10-----> Mx=2
step 2
find the y coordinate of point M
My=Ay+(2/5)*dABy
where
My is the y coordinate of point M
Ay is the y coordinate of point A
dABy is the distance AB in the y coordinate
Ay=-4
dABy=(1+4)=5
Mx=-4+(2/5)*5-----> My=-2
the coordinates of point M is (2,-2)
see the attached figure
A(-2,-4) B(8,1) <span>
let
M-------> </span><span>the coordinate that divides the directed line segment from A to B in the ratio of 2 to 3
we know that
A--------------M----------------------B
2 3
distance AM is equal to (2/5) AB
</span>distance MB is equal to (3/5) AB
<span>so
step 1
find the x coordinate of point M
Mx=Ax+(2/5)*dABx
where
Mx is the x coordinate of point M
Ax is the x coordinate of point A
dABx is the distance AB in the x coordinate
Ax=-2
dABx=(8+2)=10
</span>Mx=-2+(2/5)*10-----> Mx=2
step 2
find the y coordinate of point M
My=Ay+(2/5)*dABy
where
My is the y coordinate of point M
Ay is the y coordinate of point A
dABy is the distance AB in the y coordinate
Ay=-4
dABy=(1+4)=5
Mx=-4+(2/5)*5-----> My=-2
the coordinates of point M is (2,-2)
see the attached figure