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Nookie1986 [14]
3 years ago
13

Select all statements that are true about the linear equation. y=12x−4y=12x-4 The graph of the equation is the set of all points

that are solutions to the equation. The point (−6,7)(−6,7) is on the graph of the equation. The graph of the equation is a single point representing one solution to the equation. The point (−4,−6)(−4,−6) is on the graph of the equation.

Mathematics
2 answers:
Alex787 [66]3 years ago
4 0

Answer:

<h2>The graph of the equation is the set of all points that are solutions to the equation.</h2>

Step-by-step explanation:

The given equation is

y=12x-4

The true statement is the first one, because the graph of an equation always represent all points that are solutions. That is, all solutions for this equation are all the points placed on the line. The graph of the given linear equation is attached.

You can see in the graph that the points (-6,7) and (-4,-6) are not solutions for this equation, because they aren't on the line.

Also, you can see that the equation represents an infinite line, that is, the equation doesn't have a single solution.

Therefore, the true statement is the first one.

satela [25.4K]3 years ago
3 0
I think the answer is A,B, and D.
Where these the answers?
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6,12,8,10,16


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gizmo_the_mogwai [7]

Answer:

t=\frac{9.1-8}{\sqrt{\frac{(1.9)^2}{40}+\frac{(2.1)^2}{50}}}}=2.604  

p_v =2*P(t_{(88)}>2.604)=0.0108

So the p value is a very low value and using any significance level for given \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and there is enough evidence to conclude that the two means are significantly different at 5%

Step-by-step explanation:

Data given and notation

\bar X_{1}=9.1 represent the mean for the sample 1

\bar X_{2}=8 represent the mean for the sample 2

s_{1}=1.9 represent the sample standard deviation for the sample 1

s_{2}=2.1 represent the sample standard deviation for the sample 2

n_{1}=40 sample size for the group 1

n_{2}=50 sample size for the group 2

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean are different , the system of hypothesis would be:

Null hypothesis:\mu_{1} = \mu_{2}

Alternative hypothesis:\mu_{1} \neq \mu_{2}

If we analyze the size for the samples both are higher than 30 and the population deviations are not given, so for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

We can replace in formula (1) the results obtained like this:

t=\frac{9.1-8}{\sqrt{\frac{(1.9)^2}{40}+\frac{(2.1)^2}{50}}}}=2.604  

Statistical decision

The first step is calculate the degrees of freedom, on this case:

df=n_{1}+n_{2}-2=40+50-2=88

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p_v =2*P(t_{(88)}>2.604)=0.0108

So the p value is a very low value and using any significance level for given \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and there is enough evidence to conclude that the two means are significantly different at 5%

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