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wolverine [178]
3 years ago
8

Quick calculation 1+2+3+ ... +100=?

Mathematics
1 answer:
pogonyaev3 years ago
7 0
I read this  in a book called Number Games by Ivan Moscovich, "A famous German Mathematician, Karl Fredrich Gauss...When Gauss was a ten-year old student, his teacher wanted to keep his class busy for a long time so, he asked the students to add up all the number from 1 to 100....He realized that the first and last numbers (1 and 100) add up to 101.  The second number (2) and the next-to-the-last number also add ed to 101... and so on...He then had 100 pairs, which he multiplied by 101. Since Gauss only wanted the sum of one set of numbers from 1 to 100, he then divided the total in half."

the answer is  5050
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Hello from MrBillDoesMath!

Answer:  6 * p^(3/2) * q^4


Discussion:

We are evaluating

sqrt  { 36 * p^3 q^8 }

where "sqrt" indicates the square root and the ^ (as in q^8) means "raised to the power of:

The square root of the product is the product of the square roots. (Say that 5 time out loud quickly!). So the above equation becomes

sqrt  { 36 * p^3 q^8 }  =

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The square root of 36 is 6 as 6* 6 = 36 so the equation equals

6 *  p ^ (3/2) * q^ (8/2)        

Note that  the square root of a number, for example, r, is the same as raising the number to the (1/2) power.  That's where the (1/2) terms came from above.

But 8/2 = 4 so the equation simplifies to

6 * p^(3/2) * q^4



Thank you,

MrB

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