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yawa3891 [41]
2 years ago
12

#1 use the pythagorean theorem to find the missing side of each right triangle

Mathematics
1 answer:
Luba_88 [7]2 years ago
7 0

Answer:

Step-by-step explanation:

1-13

2-8

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There were 29 students available for the woodwind section of the school orchestra. 11 students could play the flute, 15 could pl
Dafna11 [192]

Answer:

a. The number of students who can play all three instruments = 2 students

b. The number of students who can play only the saxophone is 0

c. The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only one of the clarinet, saxophone, or flute = 4

Step-by-step explanation:

The total number of students available = 29

The number of students that can play flute = 11 students

The number of students that can play clarinet = 15 students

The number of students that can play saxophone = 12 students

The number of students that can play flute and saxophone = 4 students

The number of students that can play flute and clarinet = 4 students

The number of students that can play clarinet and saxophone = 6 students

Let the number of students who could play flute = n(F) = 11

The number of students who could play clarinet = n(C) = 15

The number of students who could play saxophone = n(S) = 12

We have;

a. Total = n(F) + n(C) + n(S) - n(F∩C) - n(F∩S) - n(C∩S) + n(F∩C∩S) + n(non)

Therefore, we have;

29 = 11 + 15 + 12 - 4 - 4 - 6 + n(F∩C∩S) + 3

29 = 24 + n(F∩C∩S) + 3

n(F∩C∩S) = 29 - (24 + 3) = 2

The number of students who can play all = 2

b. The number of students who can play only the saxophone = n(S) - n(F∩S) - n(C∩S) - n(F∩C∩S)

The number of students who can play only the saxophone = 12 - 4 - 6 - 2 = 0

The number of students who can play only the saxophone = 0

c. The number of students who can play the saxophone and the clarinet but not the flute = n(C∩S) - n(F∩C∩S) = 6 - 2 = 4

The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only the saxophone = 0

The number of students who can play only the clarinet = n(C) - n(F∩C) - n(C∩S) - n(F∩C∩S) = 15 - 4 - 6 - 2 = 3

The number of students who can play only the clarinet = 3

The number of students who can play only the flute = n(F) - n(F∩C) - n(F∩S) - n(F∩C∩S) = 11 - 4 - 4 - 2 = 1

The number of students who can play only the flute = 1

Therefore, the number of students who can play only one of the clarinet, saxophone, or flute = 1 + 3 + 0 = 4

The number of students who can play only one of the clarinet, saxophone, or flute = 4.

6 0
3 years ago
Please Help!! what value of b makes the trinomial below a perfect square?
Anna [14]
Remember, you take 1/2 of b and square it to get c

c=100
(b/2)^2=c
(b/2)^2=100
sqrt oth sides
b/2=+/-10
times both sides by 2
b=+/-20
it is 20 or -20

answe ris B
yo is right
4 0
3 years ago
52% of what number equals 39
OverLord2011 [107]
To figure this equation out, you'll have to divide 39 by 52% (0,52)

39 / 0.52 = 75

39 is 52% of 75 is your answer.

Hope this helps!
8 0
3 years ago
Read 2 more answers
Javier monthly net income is $1,500. He requests that his bank deposit 1/5 of his monthly earnings into his savings account. how
Harman [31]
1500 * 1/5
1500 * 0.2 = 300
300 * 12 = 3600
Javier contributes $3,600 a year to his savings.
5 0
2 years ago
1/6d + 2/3 = 1/4(d-2) how to solve
natita [175]
Greetings!

Solve for d.
1/6d + 2/3 = 1/4(d-2)
Distribute the Parenthesis.
1/6d + 2/3 = 1/4*d+1/4*-2
1/6d + 2/3 = 1/4d+1/4*-2/1
1/6d + 2/3 = 1/4d-2/4
Reduce.
1/6d + 2/3 = 1/4d-1/2
Add -2/3 to both sides.
(1/6d + 2/3)+(-2/3)=(1/4d-1/2)+(-2/3)
Simplify.
1/6d=1/4d-3/6-4/6
1/6d=1/4d-7/6
Add -1/4d to both sides.
(1/6d)+(-1/4d)=(1/4d-7/6)+(-1/4d)
Simplify.
2/12d)-3/12d=-7/6
-1/12d=-7/6
Divide both sides by -1/12.
(-1/12d)/-1/12=(-7/6)/-1/12
Simplify.
d=(-7/6)*-12/1
d=84/6
Reduce.
d=14/1
d=14

Hope this helps.
-Benjamin
7 0
3 years ago
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