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Yuliya22 [10]
3 years ago
9

PLEASE HELP!!

Mathematics
1 answer:
notsponge [240]3 years ago
3 0

The answer would be A. Hope this helped! :)

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The nine ring wraiths want to fly from barad-dur to rivendell. rivendell is directly north of barad-dur. the dark tower reports
Verdich [7]

Velocity of the ring wraiths relative to the air:

\vec v_{W/A}=(v_{W/A}\cos45^\circ,v_{W/A}\sin45^\circ)=\left(\dfrac{v_{W/A}}{\sqrt2},\dfrac{v_{W/A}}{\sqrt2}\right)

The speed v_{W/A} is what we want to find - this is the speed at which the wraiths are flying in the air.

(Note: \vec v denotes velocity, while v denotes speed)

Velocity of air relative to the ground:

\vec v_{A/G}=((69\,\mathrm{mph})\cos180^\circ,(69\,\mathrm{mph})\sin180^\circ)=(-69,0)\,\mathrm{mph}

The ring wraiths want their trajectory to be due north, which means their velocity relative to the ground should be

\vec v_{W/G}=(v_{W/G}\cos90^\circ,v_{W/G}\sin90^\circ)=(0,v_{W/G})

To an observer on the ground, v_{W/G} is the speed at which the wraiths would appear to be moving in the air.

The relative velocities satisify

\vec v_{W/A}+\vec v_{A/G}=\vec v_{W/G}

\implies\begin{cases}\dfrac{v_{W/A}}{\sqrt2}-(69\,\mathrm{mph})=0\\\\\dfrac{v_{W/A}}{\sqrt2}=v_{W/G}\end{cases}

\implies v_{W/A}=69\sqrt2\,\mathrm{mph}\approx98\,\mathrm{mph}

5 0
3 years ago
To decrease an amount by 8 percent, what single multiplier would you use?
Alchen [17]
That's far more problems than I usually accept in a single question, but since you're new and obviously a beginner, I'll try to help. 

<span>To Increase an amount by 7% what single multiplier would you use </span>
<span>We want 7% more than 100% of the amount, so the multiplier is </span>
<span>(100% + 7%) = 107% = 1.07 </span>
<span>[Remember that "percent" means "per hundred," so we divide a percentage by 100 to get the numerical equivalent.] </span>

<span>To Decrease an amount by 7% what single multiplier would you use </span>
<span>We want 7% less than 100% this time, so the multiplier is </span>
<span>(100% - 7%) = 93% = 0.93 </span>

<span>5 ÷ 0.1 </span>
<span>= 50 </span>

<span>(To One Decimal Place) (0.3 x 2.8)Squared </span>
<span>[Notation: around here we usually write "squared" as ^2, where the ^ is an exponentiation sign.] </span>
<span>(0.3 x 2.8)^2 = 0.84^2 = 0.7056 </span>
<span>which is 0.7 when rounded to one decimal place. </span>

<span>6.38 + 4.52 ÷ 4.71 +9.53 </span>
<span>= 6.38 + (4.52 ÷ 4.71) + 9.53 [assuming operations in the usual order] </span>
<span>= about 6.38 + 0.96 + 9.53 </span>
<span>= 16.87 </span>

<span>Expand and Simplify </span>
<span>(x + 2)(x + 3) </span>
<span>= x^2 + 2x + 3x + 6 </span>
<span>= x^2 + 5x + 6 </span>

<span>Expand and Simplify </span>
<span>(x + 2)(x - 3) </span>
<span>= x^2 + 2x - 3x - 6 </span>
<span>= x^2 - x - 6 </span>

<span>x + 1 < 5 </span>
<span>x < 4 [subtracting 1 from both sides] </span>

<span>Make n the subject of the formula.... M=3n </span>
<span>3n = M </span>
<span>n = M/3</span>
5 0
3 years ago
Help please ..............​
vlada-n [284]

Answer:

6x is indeed the Greatest Common Factor.

Step-by-step explanation:

6x[3 - y² + 2y⁶]

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Eddie is practicing wind sprints during his summer break. He’s able to run 72 meters in 12 seconds. If d represents distance and
KATRIN_1 [288]

Answer:

what grade is this in?

Step-by-step explanation:

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3 years ago
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