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mr_godi [17]
4 years ago
12

15 less than 8 times a number is 27

Mathematics
2 answers:
azamat4 years ago
6 0

Answer:

8x - 15=27

+15 +15

8x/8 = 42/8

x = 5.25

lesya692 [45]4 years ago
4 0

Answer:

5.25

Step-by-step explanation:

27 = 8a - 15

We have to find "a" here.

We add 15 to each side. The 15 cancels out on the left, and we are left with 27+15 = 42. We then have to divide by 8 on each side to get the "a" by itself.

42/8 = 5.25. We can check our work by answering the "number" with the word problem. 8 * 5.25 = 42 and then 42-15 = 27. Our number gets the answer 27, therefore the answer is 5.25!

Hope this helps.

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The weights of the apples grown on an orchard are normally distributed. The mean weight has been m0 = 9.500 ounces. Because of t
diamong [38]

Answer:

t(s) is in rejection zone then we reject H₀.

Bad weather indeed make apples weight decrease

Step-by-step explanation:

Normal Distribution

population mean    μ₀   = 9.5 ou

sample size   =  n   =  16  then we should apply t-student table

degree of fredom   df  =  n  - 1     df =  16  -  1    df  = 15

1.-Test  hypothesis

H₀     null  hypothesis                          μ₀   =  9.5    

Hₐ alternative hypothesis                   μ₀  <  9.5

One left tail-test

2.-Confidence level 95 %

α  =  0,05    and   df  = 15    from t-student table we get  t(c)  =  - 1.761

3.-Compute t(s)  

t(s)  =  [ μ  -  μ₀  ] /√s/n         t(s)  = (9.32  -  9.5 )* √16 / 0.18

t(s)  = -  0.18*√16 / 0.18

t(s)  = - 4

4.-Compare  t(s)   and t(c)

t(s) < t(c)     -4  <  - 1.761

Then  t(s)  is in the rejection zone.

5.- Decision

t(s) is in rejection zone then we reject H₀.

Farmer conclude that bad weather make apples weight decrease

6 0
4 years ago
what is an equation of the line that is perpendicular to y + 1 = -3(x-5) and passes through the point (4, 6)
Korolek [52]

\text{Let}\ k:y=m_1x+b_1\ \text{and}\ l:y=m_2x+b_2,\ \text{then}\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\l\ \parallel\ k\iff m_1=m_2\\\\\text{We have}\ y+1=-3(x-5)\to m_1=-3.\\\\\text{Therefore}\ m_2=-\dfrac{1}{-3}=\dfrac{1}{3}.\\\\\text{The point-slope form:}\ y-y_1=m(x-x_1).\\\\\text{Put the value of slope and the coordinates of the point (4, 6) to the equation}:\\\\\boxed{y-6=\dfrac{1}{3}(x-4)}

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3 years ago
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