Joe read 140 of his 300 page book. What percent of the book has he read

Find the equation of the plane that goes through three points:

frosja888 [35]

The equation of the plane that goes through these points is:

6x + 2y + z = 10.

<h3>How to find the equation of a plane given three points?</h3>

The equation of the plane is found replacing the points into the following equation:

ax + by + c = z.

For point A, we have that:

3b + c = 4.

For point B, we have that:

a + 2b + c = 0.

For point C, we have that:

-a + 6b + c = 4.

Hence the system is:

3b + c = 4.

a + 2b + c = 0.

-a + 6b + c = 4.

From the first equation, we have that:

c = 4 - 3b.

Replacing in the second, we have that:

a + 2b + 4 - 3b = 0

a - b = -4.

Replacing in the third, we have that:

-a + 6b + 4 - 3b = 4.

-a + 3b = 0.

a = 3b.

We have that a - b = -4, hence:

3b - b = -4

2b = -4

b = -2.

a = 3b, hence a = -6.

c = 4 - 3b -> c = 10.

Hence the equation is:

ax + by + c = z.

z = -6x - 2y + 10

6x + 2y + z = 10.

More can be learned about the equation of a plane at brainly.com/question/13854649

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9 months ago

Assume that the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder. Based on this assumption,

kompoz [17]

If the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder, then its volume is

$V_{flask}=V_{sphere}+V_{cylinder}.$

Use following formulas to determine volumes of sphere and cylinder:

$V_{sphere}=\dfrac{4}{3}\pi R^3,\\ \\V_{cylinder}=\pi r^2h,$

wher R is sphere's radius, r - radius of cylinder's base and h - height of cylinder.

Then

$V_{sphere}=\dfrac{4}{3}\pi R^3=\dfrac{4}{3}\pi \left(\dfrac{4.5}{2}\right)^3=\dfrac{4}{3}\pi \left(\dfrac{9}{4}\right)^3=\dfrac{243\pi}{16}\approx 47.71;$
$V_{cylinder}=\pi r^2h=\pi \cdot \left(\dfrac{1}{2}\right)^2\cdot 3=\dfrac{3\pi}{4}\approx 2.36;$
$V_{flask}=V_{sphere}+V_{cylinder}\approx 47.71+2.36=50.07.$

Answer 1: correct choice is C.

If both the sphere and the cylinder are dilated by a scale factor of 2, then all dimensions of the sphere and the cylinder are dilated by a scale factor of 2. So

R'=2R, r'=2r, h'=2h.

Write the new fask volume:

$V_{\text{new flask}}=V_{\text{new sphere}}+V_{\text{new cylinder}}=\dfrac{4}{3}\pi R'^3+\pi r'^2h'=\dfrac{4}{3}\pi (2R)^3+\pi (2r)^2\cdot 2h=\dfrac{4}{3}\pi 8R^3+\pi \cdot 4r^2\cdot 2h=8\left(\dfrac{4}{3}\pi R^3+\pi r^2h\right)=8V_{flask}.$