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4 years ago

Pleas help me solve this for x Need answer ASAP!

Mathematics

2 answers:

Delvig [45]4 years ago

5 0

The answer is 40 ! Hope this helps

irinina [24]4 years ago

3 0

Answer:

Step-by-step explanation:

$3x = 120 you would have to divide 3 by 3 and get 'x' by itself and then you would have to divide 120 by 3 and then you would get 40 and so then your answer would be x = 40$

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Solve the quadratic equation by completing the square. 6x2 + 4x - 5 = 0

Nikitich [7]

Answer:

$x_{1}=-\frac{2+\sqrt{34}}{6}$

$x_{2}=-\frac{2-\sqrt{34}}{6}$

Step-by-step explanation:

Quadratic Equation given:

$6x^2 + 4x - 5 = 0$

Start dividing both sides by 6.

$\frac{6}{6} x^2 +\frac{4}{6} x - \frac{5}{6} = \frac{0}{6}$

$x^2 +\frac{2}{3} x - \frac{5}{6} = 0$

$x^2 +\frac{2}{3} x = \frac{5}{6}$

Once, $\left( \frac{2}{3} \cdot \frac{1}{2} \right)^2=\frac{1}{9}$

$x^2 +\frac{2}{3} x+\frac{1}{9} = \frac{5}{6}+\frac{1}{9}$

$\left(x+\frac{1}{3} \right)^2 = \frac{17}{18}}$

$x+\frac{1}{3} =\pm\sqrt{\frac{17}{18}} }$

Solving $\sqrt{\frac{17}{18}}$

$\sqrt{\frac{17(18)}{18(18)}}= \sqrt{\frac{306}{324}}=\frac{3\sqrt{34} }{18} =\frac{\sqrt{34} }{6}$

Then,

$x+\frac{1}{3} =\pm\frac{\sqrt{34} }{6}$

$x =-\frac{1}{3} \pm\frac{\sqrt{34} }{6}$

$x_{1}=-\frac{2+\sqrt{34}}{6}$

$x_{2}=-\frac{2-\sqrt{34}}{6}$

6 0

3 years ago

What is the value of the expression (8^2/3)^1/2

nikklg [1K]

$\left( 8^{\frac{2}{3}} \right)^{\frac{1}{2}}\implies \left( (2^3)^{\frac{2}{3}} \right)^{\frac{1}{2}}\implies 2^{3\cdot \frac{2}{3}\cdot \frac{1}{2}}\implies 2^{\frac{1}{1}}\implies 2$