First calculate the distance covered going down:
d_down = (16 m / s) * 8 s = 128 m
Then the distance going up is:
d_up = 71 m
So the distance from the ledge to the nest is:
d = 128 m – 71 m = 57 m
Therefore the elevation is:
<span>elevation = 1364 m + 57 m = 1421 m</span>
The graph of the system is
where y= -4x-2 is in red, and y= -4x-5 is in blue.
Given that the lines are parallel, then there is no solution to the system of equations.
Answer: Yes. When you solve your equations, you're solutions will change a little bit. It's good because it'll give you the right answer.
I hope this helps you and I hope it's right. ☺
Answer: (b)-175 ft
Step-by-step explanation:
In 
![\angle ACB=\angle ECD\quad [\text{vertically opposite angles}]\\\angle ABC=\angle CDE\quad [\text{Each angle is }90^{\circ}]\\\therefore \triangle ABC \sim\ \triangle CDE\quad [\text{by AA similarity criteria}]](https://tex.z-dn.net/?f=%5Cangle%20ACB%3D%5Cangle%20ECD%5Cquad%20%5B%5Ctext%7Bvertically%20opposite%20angles%7D%5D%5C%5C%5Cangle%20ABC%3D%5Cangle%20CDE%5Cquad%20%5B%5Ctext%7BEach%20angle%20is%20%7D90%5E%7B%5Ccirc%7D%5D%5C%5C%5Ctherefore%20%5Ctriangle%20ABC%20%5Csim%5C%20%5Ctriangle%20CDE%5Cquad%20%5B%5Ctext%7Bby%20AA%20similarity%20criteria%7D%5D)
(ii)for similar triangles, we can write
In similar figures the statement is written in such a way so that corresponding sides and equal angles are placed at same place .
The given similarity statement can be written as KLMN ~ PQRS
The question is asking us to find the angle which corresponds to <N
In the statement N occurs at the last place in the letter KLMN so we will look at the same place in the letter PQRS,
The letter S occupies the same place as N
So we say <N corresponds to <S
The first option is right
