Question

3. The two data sets show random samples of the costs, in dollars, of cars purchased at two dealerships yesterday.

Answer 1

Order the two data sets from least to greatest:

Dealership 1:
25,000, 37,000, 42,000, 45,000, 120,000

Dealership 2:
18,000, 19,000, 28,000, 33,000, 95,000

To find the median of each data set, add the number of terms by 1 and divide by 2 to determine which term is the median:

$(5 + 1) / 2 = 6 / 2 = 3$

The third term of each data set will be the median.

Dealership 1's median is $42,000, and dealership 2's median is $28,000.

To find the mean of each data set, add all of the terms, then divide by the amount of terms.

Dealership 1:

$\frac{25,000 + 37,000 + 42,000 + 45,000 + 120,000}{5} = \frac{269,000}{5} = 53,800$

Dealership 2:

$\frac{18,000+19,000+28,000+33,000+95,000}{5} = \frac{193,000}{5} = 38,600$

Dealership 1's mean is $53,800, and dealership 2's mean is $38,600.

The measure of center that will provide the most accurate estimate of the costs of cars purchased at the two dealership is the mean, as it provides the average cost of a car.

Answer 2

Hey there! :)

Mean: The average;calculated by adding all the numbers and dividing by how many there are.

Median: The middle number
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(a) Mean (Dealership 1)
25,000 + 42,000 + 37,000 + 45,000 + 12,000 = 269,000

269,000 ÷ 5 = 53,800

Mean = 53,800

(a) Median(Dealership 1)

Order the numbers

25,000, 37,000, 42,000, 45,000, 120,000

Median = 42,000
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(a) Mean (Dealership 2)

28,000 + 95,000 + 18,000 + 19,000 + 33,000 = 193,000

193,000 ÷ 5 = 38,600

Mean = 38,600

(a) Median(Dealership 2)

Order the numbers

18,000, 19,000, 28,000, 33,000, 95,000

Median = 28,000
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(b) Mean because it's similar to summarizing the whole data set

Hope this helps :)