Answer:
A customer who sends 78 messages per day would be at 99.38th percentile.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Average of 48 texts per day with a standard deviation of 12.
This means that 
a. A customer who sends 78 messages per day would correspond to what percentile?
The percentile is the p-value of Z when X = 78. So



has a p-value of 0.9938.
0.9938*100% = 99.38%.
A customer who sends 78 messages per day would be at 99.38th percentile.
The average number of pins he knocks down per role is about 7 1/3
10 + 9 + 7 = 22
22 divided by 3 = 7 1/3
so his pin total would probably be 44
<u>x</u><u>=</u><u>3</u><u>0</u><u>°</u>
Answer:
Cos x°=adjacent/hypotenuse
Cos x°=45/52
x°=Cos-¹(45/52)
x°=30°
I think it’s 4x+-2x+1
Sorry if it’s wrong but can you help me with my question?
Answer:
we need a picture of the ghraph