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san4es73 [151]
3 years ago
12

28/36 reduced fraction

Mathematics
2 answers:
taurus [48]3 years ago
8 0
You can easily keep simplifying this fraction by 2 until you can't simplify it anymore, because they're both even.

\frac{28}{36} =  \frac{14}{18} =  \frac{7}{9}

It can be faster this way for most people, but you can also just find what number goes into both numbers evenly.
4 goes into both numbers.

28\div4=7\\36\div4=9\\\\ \frac{7}{9}
ratelena [41]3 years ago
6 0
28/4 = 7,
36/4 = 9,
Place the 7 over the 9 and you get 7/9!
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Answer:

Domain : {10, 15, 19, 32}

Range: {-1, 5, 9}

Step-by-step explanation:

As the table of the relation is given as follows:

<em>X                Y</em>

<em>10               5</em>

<em>15               9</em>

<em>19               -1</em>

<em>32             5  </em>

From this table, we can define the relation by combining the ordered pairs from the table. Each and every order pair consists of x-coordinate and corresponding y-coordinate of any corresponding point.

So, the relation from the table can be made as follows:

                            relation : {(10, 5), (15, 9), (19, -1), (32, 5)}

Domain of a relation consists of all the x-coordinates (first elements) of order pairs.

Range of a relation consists of all the y-coordinates (second elements) of ordered pairs.

So, domain  and range of relation will be as follows:

                                  Domain : {10, 15, 19, 32}

                                  Range: {-1, 5, 9}

<em>Note: If there is any </em><em>duplicate</em><em> element in any x or y-coordinate of any ordered pair, it will be written only </em><em>once </em><em>when we determine domain and range. Here, in this example, 5 is duplicate, so, it will be mentioned only one time when we determine the range of this relation.</em>

Keywords:  domain, relation, range

Learn more about domain and range of a relation from brainly.com/question/11422136

#learnwithBrainly

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3 years ago
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dimulka [17.4K]

Answer:

a) 48.21 %

b) 45.99 %

c) 20.88 %

d) 42.07 %

e) 50 %

Note: these values represent differences between z values and the mean

Step-by-step explanation:

The test to carry out is:

Null hypothesis  H₀    is                           μ₀ = 30  

The alternative hypothesis                      m  ≠ 30

In which we already have the value of z for each case therefore we look  directly the probability in z table and carefully take into account that we had been asked for differences from the mean (0.5)

a)  z = 2.1   correspond to  0.9821  but mean value is ubicated at 0.5 then we subtract    0.9821 - 0.5  and get 0.4821   or 48.21 %

b)  z = -1.75   P(m) = 0.0401     That implies the probability of m being from that point p to the end of the tail, the difference between this point and the mean so 0.5 - 0.0401 = 0.4599 or 45.99 %

c)  z = -.55    P(m) = 0.2912    and this value  for same reason as before is 0.5 - 0.2912 = 0.2088  or 20.88 %

d)  z = 1.41     P(m) = 0.9207    0.9207 -0.5     0.4207  or  42.07 %

e)  z = -5.3   P(m) = 0    meaning there is not such value in z table is too small to compute  and difference to mean value will be 0.5  

d)  z= 1.41      P(m) =

4 0
2 years ago
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