Solve the inequality. |2k + 1| ≥ 5

1 answer:

6 0

If you remove the absolute value of |2k+1| ≥ 5, you will get:

a) 2k+1 ≥ 5 and b) 2k+1≤ - 5. (for the negative , you flip the inequality sign)
Hence

a) 2k+1 ≥ 52 → k≥5-1 and k≥ 2 And
b) 2k+1 ≤ - 5 → k≤ - 5- 1 and k ≤ - 3

Then -3 ≥ k ≥ 2

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