Eight balls numbered from 1 to 8 are placed in an urn. One ball is selected at random. Find the probability that it is
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Answer:
Step-by-step explanation:
Answer:
The probability of the event that first ball that is drawn is blue is .
Step-by-step explanation:
Probability:
If S is is an sample space in which all outcomes are equally likely and E is an event in S, then the probability of E,denoted P(E) is
Given that,
An urn contains two balls B₁ and B₂ which are blue in color and W₁,W₂ and W₃ which are white in color.
Total number of ball =(2+3) =5
The number ways of selection 2 ball out of 5 ball is
=5²
=25
Total outcomes = 25
List of all outcomes in the event that the first ball that is drawn is blue are
B₁B₁ , B₁B₂ , B₁W₁ , B₁W₂ , B₁W₃ , B₂B₁ , B₂B₂ , B₂W₁ , B₂W₂ , B₂W₃
The number of event that the first ball that is drawn is blue is
=10.
The probability of the event that first ball that is drawn is blue is