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marin [14]
3 years ago
6

The arcade sells individual tokens for .25 each. If a package contains 25 tokens, how much would you save by buying a package of

25 tokens instead of 25 individual tokens?
Mathematics
1 answer:
Korvikt [17]3 years ago
7 0
Buying 25 individual tokens would be $6.25
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Which compound inequalities have the solution set represented by the given graph? Check all that apply
Contact [7]

We check with each options

'Or' represents the intersection of two graphs

'And' represents two separate graphs'

We have two separate shaded part in the given graph

So we ignore the options that has 'and' in between

LEts check first  and second option

\frac{x}{2}=13

Simplify the first part and second part

multiply both sides by 2 .

x < 2  or  4x - 2 > = 26

solve 4x-2 > = 26

add 2 on both sides and then divide both sides by 4

4x >= 28

x >= 7

So solution is x<2 or x>=7 . that is the graph on number line

Lets check with second option

3x-3<3  or  2x+8>=22

add 3 on both sides

3x < 6

divide both sides by 3

so x< 2

2x+8>=22

subtract 8 on both sides

2x >= 30

divide both sides by 2

x >= 15

x<2  or x>=15 that does not satisfies the graph

So option A is correct



7 0
4 years ago
Read 2 more answers
Factor completly 108-3x^2​
Sergeu [11.5K]
The fully factored polynomial is −3(x−6)(x+6).
3 0
3 years ago
Priya's cat weighs 5 1/2 pounds and her dog weighs 8 1/4 pounds.
Lilit [14]

Answer: The cat is 2/3 times as heavy as the dog.


Step-by-step explanation:

The weight of Priya's cat =5\frac{1}{2}\ pounds

Now, 5\frac{1}{2}=\frac{11}{2}\ pounds

The weight of her dog =8\frac{1}{4}\ pounds

8\frac{1}{4}=\frac{33}{4}\ pounds

Let cat is n times heavy as dog.

Then n=\text{cat's weight}\div\text{dog's weight}

n=\frac{{11}{2}\div\frac{33}{4}\\\Rightarrow\ n=\frac{11}{2}\times\frac{4}{33}\\\Rightarrow\ n=\frac{2}{3}

Hence, The cat is 2/3 times as heavy as the dog.

5 0
3 years ago
Read 2 more answers
The monthly amounts spent for food by families of four receiving food stamps approximates a symmetrical, normal distribution. Th
e-lub [12.9K]

Answer:

95% of monthly food expenditures are between $110 and $190.

Step-by-step explanation:

Given : The monthly amounts spent for food by families of four receiving food stamps approximates a symmetrical, normal distribution. The sample mean is $150 and the standard deviation is $20.

To find : Using the Empirical rule, about 95% of the monthly food expenditures are between which of the following two amounts?

Solution :

At 95% of the data is between two standard deviation to left and right of the mean is given by,

To the left side, \bar{x}-2\sigma

To the right side, \bar{x}+2\sigma

We have given,

The sample mean \bar{x}=\$150

The standard deviation \sigma=\$20

Substitute in the formula,

\bar{x}-2\sigma

=150-2(20)

=150-40

=110

\bar{x}+2\sigma

=150+2(20)

=150+40

=190

Therefore, 95% of monthly food expenditures are between $110 and $190.

6 0
3 years ago
Given P(x) = 2x3+ 3x2- x + 4, find P(0) and P(-2).
pshichka [43]

9514 1404 393

Answer:

  P(0) = 4

  P(-2) = 2

Step-by-step explanation:

Put the value where the variable is and do the arithmetic.

  P(0) = 2·0³ +3·0² -0 +4

  P(0) = 4

__

  P(-2) = 2·(-2)³ +3·(-2)² -(-2) +4 = 2(-8) +3(4) +2 +4

  P(-2) = -16 +12 +2 +4

  P(-2) = 2

6 0
3 years ago
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