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2 years ago

There were 60 ducks living in a pond. If the number living at the pond increased by 30%, how many ducks now live at the pond?

Mathematics

1 answer:

timama [110]2 years ago

3 0

Answer:

Step-by-step explanation:

You take the original total: 60, and multiply it by 30 to get 1,800. You then divide 1,800 by 100 to get 18. 18 is your 30%. Now, you add the 30% to 60 getting your total number of ducks: 78.

The equation version:

$\frac{a}{60} = \frac{30}{100}$

It is just proportions.

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7/7q+21= x /5q^2-45 then x=?

anzhelika [568]

Answer:

x = 5q - 15

Step-by-step explanation:

$\frac{7}{7q+21}=\frac{x}{5q^{2}-45}\\\\\frac{7}{7(q+3)}=\frac{x}{5 (q^{2} -9)}\\\\frac{1}{q+3}=\frac{x}{5*(q^{2}-3^{2})}\\\\\frac{1}{q+3}=\frac{x}{5(q+3)(q-3)}\\\\\frac{1}{q+3}*5*(q+3)(q-3)=x\\\\5(q-3)=x\\\\x= 5q-15$

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3 years ago

The diagonal of a square is 8 cm.

VladimirAG [237]

the length of the side of this square is $4\sqrt{2} \:or \:5.65$ cm

Answer:

Solutions Given:

let diagonal of square be AC: 8 cm

let each side be a.

As diagonal bisect square.

let it forms right angled triangle ABC .

Where diagonal AC is hypotenuse and a is their opposite side and base.

By using Pythagoras law

hypotenuse ²=opposite side²+base side²

8²=a²+a²

64=2a²

a²= $\frac{64}{2}$

a²=32

doing square root on both side

$\sqrt{a²}=\sqrt{32}$

a=± $\sqrt{2*2*2*2*2}$

a=±2*2 $\sqrt{2}$

Since side of square is always positive so

a=4 $\sqrt{2}$ or 5.65 cm

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