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QveST [7]
3 years ago
10

On an Android device, where can a user find the correct app to use to sync contacts and apps among devices?

Computers and Technology
1 answer:
12345 [234]3 years ago
3 0
The user can use the Play store on there android device
You might be interested in
HELP I WILL MARK BRAINLIEST!!! I NEED ASAP!!!
Alex777 [14]

#This is a way without a loop

friends = list(map(str,input("Enter Names: ").split()))

print(sorted(friends))

#This is a way with a loop (for&&while)

friends = list(map(str,input("Enter Names: ").split()))

cool = True

while cool:

   cool = False

   for i in range(len(friends)-1):

       if friends[i] > friends[i+1]:

           coo = friends[i]

           friends[i] = friends[i+1]

           friends[i+1] = coo

           cool = True

print(friends)

4 0
3 years ago
What is Application Software ??
Paraphin [41]


Hi Pupil Here's Your Answer ::



➡➡➡➡➡➡➡➡➡➡➡➡➡


Application software and software that are created to facilitate/perform a specific type of real life application directly for the end user. These are available in the market as single readymade software or as an integrated package like MS Office, Visual Studio or Adobe integrated suite.


There are three types of application software which you would know about ::

# General Purpose Application Software.

# Special Purpose Application Software.

# Customized or Bespoke Purpose Application Software.


⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅




Hope this helps .........
6 0
3 years ago
Read 2 more answers
Create a Binary Expressions Tree Class and create a menu driven programyour program should be able to read multiple expressions
solong [7]

Answer:

Explanation:

Program:

#include<iostream>

#include <bits/stdc++.h>

using namespace std;

//check for operator

bool isOperator(char c)

{

switch(c)

{

case '+': case '-': case '/': case '*': case '^':

return true;

}

return false;

}

//Converter class

class Converter

{

private:

string str;

public:

//constructor

Converter(string s):str(s){}

//convert from infix to postfix expression

string toPostFix(string str)

{

stack <char> as;

int i, pre1, pre2;

string result="";

as.push('(');

str = str + ")";

for (i = 0; i < str.size(); i++)

{

char ch = str[i];

if(ch==' ') continue;

if (ch == '(')

as.push(ch);

else if (ch == ')')

{

while (as.size() != 0 && as.top() != '('){

result = result + as.top() + " ";

as.pop();

}

as.pop();

}

else if(isOperator(ch))

{

while (as.size() != 0 && as.top() != '(')

{

pre1 = precedence(ch);

pre2 = precedence(as.top());

if (pre2 >= pre1){

result = result + as.top() + " ";

as.pop();

}

else break;

}

as.push(ch);

}

else

{

result = result + ch;

}

}

while(as.size() != 0 && as.top() != '(') {

result += as.top() + " ";

as.pop();

}

return result;

}

//return the precedence of an operator

int precedence(char ch)

{

int choice = 0;

switch (ch) {

case '+':

choice = 0;

break;

case '-':

choice = 0;

break;

case '*':

choice = 1;

break;

case '/':

choice = 1;

break;

case '^':

choice = 2;

default:

choice = -999;

}

return choice;

}

};

//Node class

class Node

{

public:

string element;

Node *leftChild;

Node *rightChild;

//constructors

Node (string s):element(s),leftChild(nullptr),rightChild(nullptr) {}

Node (string s, Node* l, Node* r):element(s),leftChild(l),rightChild(r) {}

};

//ExpressionTree class

class ExpressionTree

{

public:

//expression tree construction

Node* covert(string postfix)

{

stack <Node*> stk;

Node *t = nullptr;

for(int i=0; i<postfix.size(); i++)

{

if(postfix[i]==' ') continue;

string s(1, postfix[i]);

t = new Node(s);

if(!isOperator(postfix[i]))

{

stk.push(t);

}

else

{

Node *r = nullptr, *l = nullptr;

if(!stk.empty()){

r = stk.top();

stk.pop();

}

if(!stk.empty()){

l = stk.top();

stk.pop();

}

t->leftChild = l;

t->rightChild = r;

stk.push(t);

}

}

return stk.top();

}

//inorder traversal

void infix(Node *root)

{

if(root!=nullptr)

{

cout<< "(";

infix(root->leftChild);

cout<<root->element;

infix(root->rightChild);

cout<<")";

}

}

//postorder traversal

void postfix(Node *root)

{

if(root!=nullptr)

{

postfix(root->leftChild);

postfix(root->rightChild);

cout << root->element << " ";

}

}

//preorder traversal

void prefix(Node *root)

{

if(root!=nullptr)

{

cout<< root->element << " ";

prefix(root->leftChild);

prefix(root->rightChild);

}

}

};

//main method

int main()

{

string infix;

cout<<"Enter the expression: ";

cin >> infix;

Converter conv(infix);

string postfix = conv.toPostFix(infix);

cout<<"Postfix Expression: " << postfix<<endl;

if(postfix == "")

{

cout<<"Invalid expression";

return 1;

}

ExpressionTree etree;

Node *root = etree.covert(postfix);

cout<<"Infix: ";

etree.infix(root);

cout<<endl;

cout<<"Prefix: ";

etree.prefix(root);

cout<<endl;

cout<< "Postfix: ";

etree.postfix(root);

cout<<endl;

return 0;

}

3 0
3 years ago
Windows 10 features a storage solution called Storage Spaces. What is the name of the Storage Spaces feature that allows allocat
rewona [7]

Answer:

Data resiliency.

Explanation:

Spaces for storage may involve resilience to the information. Selecting a resiliency solution implies whether they assign capacity towards redundant details. The information resiliency choice regarding storage facilities.

Two-way mirror needs two capacity units or more. The information is engraved on both computers. Two-way mirror enables twice the volume of storage assigned to that of the storage capacity as such system capacity. This choice will prevent you against loss of a specific storage unit.

7 0
3 years ago
Use C++:
AveGali [126]

Answer:

result = pow(10,5);

Explanation:

A complete code in C++ with the necesary header file for the math class is given below:

#include <iostream>

//import the header file to use the power function

#include<cmath>

using namespace std;

int main()

{

   double base = 10.0;

   double result;

  //Use Power function to raise base to power of 5

   result = pow(10,5);

   //print out the result

   cout<<result;

   return 0;

}

5 0
3 years ago
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