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QveST [7]
3 years ago
10

On an Android device, where can a user find the correct app to use to sync contacts and apps among devices?

Computers and Technology
1 answer:
12345 [234]3 years ago
3 0
The user can use the Play store on there android device
You might be interested in
I need a C++ program to ask the user to put in different numbers until zero is pressed then the program counts the numbers that
frozen [14]

Answer:

#include <iostream>

using namespace std;

int main()

{

int input = 0;

int count = 0;

int sum = 0;

int sumNegative = 0;

while (true) {

 cout << "Enter a number: ";

 cin >> input;

 if (input == 0) break;

 count++;

 sum += input;

 if (input < 0) {

  sumNegative += input;

 }

}

cout << "Count of the numbers: " << count << endl;

cout << "Sum of all the numbers: " << sum << endl;

cout << "Sum of the negative numbers: " << sumNegative << endl;

}

Explanation:

Your requirements regarding the sum and the negative numbers was a bit vague so I just did something you can probably adjust easily to your liking.

7 0
3 years ago
Programs for embedded devices are often written in assembly language. Some embedded processors have limited instructions, like M
oksano4ka [1.4K]

Answer:

#include <iostream>

using namespace std;

int main()

{

   char address[2];

   int tag, firstBit, secondBit, setNumber;

   int cache[4][2]={{1,5}, {2,4}, {3,2}, {6,0}};

   cout << "Enter the address as hex(in small letters: "<

   cin >> address;

   for (int i < 0; i < 8; i++){

       if (address[0] == '0'){

           tag = 0;

           firstBit = 0;

        } else if (address[0] == '1'){

           tag = 0;

           firstBit = 1;

        } else if (address[0] == '2'){

           tag =1;

           firstBit = 0;

        } else if (address[0] == '3'){

           tag = 1;

           firstBit = 1;

        } else if (address[0] == '4'){

           tag = 2;

           firstBit = 0;

        } else if (address[0] == '5'){

           tag = 2;

           firstBit = 1;

        }  else if (address[0] == '6'){

           tag = 3;

           firstBit = 0;

       } else if (address[0] == '7'){

           tag = 3;

           firstBit = 1;

       }  else if (address[0] == '8'){

           tag = 4;

           firstBit = 0;

       } else if (address[0] == '9'){

           tag = 4;

           firstBit = 1;

       }   else if (address[0] == 'A'){

           tag = 5;

           firstBit = 0;

       } else if (address[0] == 'B'){

           tag = 5;

           firstBit = 1;

       }  else if (address[0] == 'C'){

           tag = 6;

           firstBit = 0;

       } else if (address[0] == 'D'){

           tag = 6;

           firstBit = 1;

        }  else if (address[0] == 'E'){

           tag = 7;

           firstBit = 0;

       } else if (address[0] == 'F'){

           tag = 7;

           firstBit = 1;

       } else{

           cout<<"The Hex number is not valid"<< endl;

        }

   }

   if(address[1]>='0' && address[1]<'8'){

       secondBit = 0;

  }  else if(address[1]=='8'|| address[1]=='9'||(address[1]>='a' && address[1]<='f')){

       secondBit = 1;

   }  else{

       cout<<"The Hex number is not valid"<< endl;  

       return 0;

   }

   setNumber = firstBit * 2 + secondBit;

   if(cache[setNumber][0]==tag || cache[setNumber][1]==tag){

       cout<<"There is a hit";

   } else{

       cout<< "There is a miss";

   }

   return 0;

}

Explanation:

The C++ source code prompts the user for an input for the address variable, then the nested if statement is used to assign the value of the firstBit value given the value in the first index in the address character array. Another if statement is used to assign the value for the secondBit and then the setNumber is calculated.

If the setNumber is equal to the tag bit, Then the hit message is printed but a miss message is printed if not.

4 0
3 years ago
When you log into quickbooks online account whose books can you directly access and manage?
MArishka [77]

Answer: your books and the ones you are given access to.

Explanation: quickbooks goes from day to day bookkeeping to month and year end financial reports and tax filing. businesses use to manage daily sales and expenses and also keep track of daily transactions. They can involve or outsource bookkeepers or choose to run in-house operations. In doing this they would have access to all their books or decide to give virtual access to their outsourced bookkeeper/accountant. Quickbooks has multiple features concerning user access and privacy. A quick books user, in this case the business, can restrict access for each user it decides to add. The user can decide to give free access to all books or decide to restrict to a few files. Example, the business may add an accountant as one of its users and decide to restrict the accountant to its payroll files, depending on the agreement.

3 0
3 years ago
Mariel types a sentence. She then decides to include that sentence four more times. She then decides she only wants the sentence
Minchanka [31]
CTRL Z and CTRL Y
(undo)_____(redo)
8 0
3 years ago
Read 2 more answers
Beth would like to eavesdrop on network traffic resulting from users browsing the Web. Which port would provide her with the mos
Elis [28]

Answer:

port 80

Explanation:

port 80 is http. port 443 is https. so if you are trying to be a sneaky little person and eavesdrop on people, eavesdrop on port 80 not port 443 because port 80 is unsecured plaintext data transmission over websites

7 0
2 years ago
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