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Valentin [98]
3 years ago
15

Given ​ f(x)=x^2−2x−5​. Enter the quadratic function in vertex form.

Mathematics
1 answer:
FrozenT [24]3 years ago
8 0

Answer:

f(x) = (x-1)^2-6

Step-by-step explanation:

Rewrite the quadratic using the method of completing the square:

x^2-2x-5=(x^2-2x+1)-1-5=(x-1)^2-6\\f(x) = (x-1)^2-6

From this form it is immediately clear that the vertex of the parabola is at x=1 and its y-intercept at -6.

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i can't really see the image but i'm sure it's pretty cool (:

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