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Dimas [21]
3 years ago
12

100) 4030 What’s the greatest common factor

Mathematics
1 answer:
Dima020 [189]3 years ago
5 0

Answer: 10

Step-by-step explanation:

100/10=10

4030/10=403

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Find the surface of the triangular prism
svetoff [14.1K]

Answer:

Step-by-step explanation:

6²+8²=36+64=100=10²

so it is a right angled triangular prism.

surface area=2×(1/2 ×8×6)+(6+8+10)×7

=48+980

=1028 sq. m.

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Please help!!! I.m confused with the problem
Oxana [17]

Answer:

C

Step-by-step explanation:

Make the equation from the blocks:

-7x + 7 = 5x + 16

Then simplify:

Subract 7 from both sides:

-7x = 5x + 9

Add 7x:

0 = 12x + 9

Subtract 9:

-9 = 12x

x = -9/12 = -3/4

7 0
3 years ago
Bridal Solutions, which sells European wedding dresses, has the following weekly
earnstyle [38]

Answer:

Step-by-step explanation:

Given the weekly revenue and cost function

R(d) = 12000

C (d) = 350d + 5000

A firm break even point occurs when the amount of revenue is equal to the cost.

If the company Bridal solution breaks even then C(d) = R(d)

350d + 5000 = 12000

350d = 12000 - 5000

350d = 7000

divide both sides by 350

350d/350 = 7000/350

d = 20

Hence the total number of wedding dressing to be sold by Bridal Solutions for them to break even is 20 dresses.

3 0
3 years ago
Jon is hitting baseballs. When he tosses the ball into the air, his hand is 5 feet above the ground. He hits the ball when it fa
vazorg [7]

Answer:

Time  that will pass before Jon hits the ball is 0.5 seconds  

The maximum height the ball attains is 6.875 feet

Step-by-step explanation:

Step 1: To find out how much time passes before Jon hits the ball

The height he hits the ball when it falls is 4 feet

so,

4 =  - 16t^2 + 6t + 5

4 + 16t^2 - 6t - 5 = 0

16t^2 - 6t -1 = 0 -------------------------(1)

Solving eq(1) using quadratic formula, we get

t =  \frac{-b \pm\sqrt{b^2-4ac}}{2a}

t =  \frac{-(-6) \pm\sqrt{(-6)^2-4(16)(-1)}}{2(16)}

t =  \frac{6 \pm\sqrt{36+64}}{32}

t =  \frac{6 \pm\sqrt{100}}{32}

t =  \frac{6 \pm10}{32}

Taking only the positive value

t =  \frac{16}{32}

t = 0.5 seconds

Step 2: To find the maximum height of the ball

Max height  will be reached at [\frac{-b}{2a}] sec

=\frac{-b}{2a}

\\ = \frac{-(-6)}{2\times16}\\

= \frac{6}{32}

Now the height at t= \frac{6}{32} is

16( \frac{6}{32})^2 - 6(  \frac{6}{32}) -1 = h

( \frac{6}{2})^2 -   \frac{36}{32} -1 = h

( 3)^2 -  1.125  -1 = h

9 -  1.125  -1 = h

6.875  =  h

3 0
4 years ago
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