Given equation is
The given equation is in the form of
a^2= 16 , so a=4
b^2 = 9 so b= 4
The value of 'a' is greater than the value of 'b'
So it is a Horizontal hyperbola
First two graphs are horizontal hyperbola
Here center is (h,k)
h= 5 and k =2 from the given equation
So center is (5,2)
Now we find vertices
Vertices are (h+a,k) and (h-a,k)
We know h=5, k=2 and a=4
So vertices are (9,2) and (1,2)
Second graph having same vertices and center
The correct graph is attached below
Answer:
absolute max is 120 and absolute min is -8
Step-by-step explanation:
Find critical numbers
f'(x) = 3x^2 - 12x + 9 = 0
= 3(x^2 - 4x + 3) = 0
3(x-3)(x-1) = 0
(x-3) = 0 or (x-1)=0
x = 1,3
Test them!
x<1 Sign of f' on this interval is positive
1<x<3 Sign of f' on this interval is negative
x>3 Sign of f' on this interval is positive
f(x) changes from positive to negative at x = 1 which means there is a relative maximum here.
f(x) changes from negative to positive at x = 3 which means there is a relative minimum here.
Test the endpoints to find the absolute max and min.
f(-1) = -8
f(1) = 12
f(3) = 8
f(7) = 120
The absolute maximum value of f is 120 and the absolute minimum value of f is -8.
What the triangle format? what does it look like? it all depends.
weekly salary is 650$
the number of days in a week is 7.
7 days salary is 650$
one day salary is 650/7
the number of days in semi month is 30/2 = 15 days
so the salary of semi month is 15*650/7 = 1392.85 $
so the salary of semi month is 1392.85 $.
Answer:
A. linear
Step-by-step explanation:
A linear model is the best-fitting regression model for the data plot because for similar variations in x values, the variation in y values are also similar, that is, if you take points (x1, y1), (x2, y2) and (x3, y3) the y1 - y2 is similar to y2 - y3, when x2 - x1 is also similar to x3 - x2.
