Answer:
scale factor P to Q: 4/5 scale factor Q to P: 5/4
Step-by-step explanation:
Divide original length over new length and you'll get the scale factor.
The order of magnitude for total attended for a high school football team is 3
<h3>How to determine the
order of magnitude?</h3>
The given parameters are:
Average number of fan = 1000
Number of home games = 5
The total number of fans in the 5 games is:
Total number of fans = Average number of fan * Number of home games
Substitute known values in the above equation
Total number of fans = 1000 * 5
Express 1000 as 10^3
Total number of fans = 10^3 * 5
Rewrite the equation as:
Total number of fans = 5 * 10^3
The power of 10 represents the order of magnitude
Since the power of 10 is 3, the order of magnitude is 3
Hence, the order of magnitude for total attended for a high school football team that averages 1,000 fans for each of its 5 home games is 3
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Answer:
The wrt=itten expressions are too difficult to interpret properly. I did my best but I don't see any of the answers as equivalent to <u>-3x - 2y, so please check my interpretations of the answer options.</u>
Step-by-step explanation:
"Negative 3 x minus one-half 4 y"
-3x- (1/2)4y
<u>or -3x - 2y</u>
<u>=====</u>
The answer options are too garbled for me to make sense of them. Are they:
1. 2 y minus 5 x minus one-half 2 y : 2y -5x - (1/2)2y; <u>y -5x</u> ?
2. 2 x Negative 2 x minus one-half 6 y : 2(-2x)- (1/2)6y; <u>-4x - 3y</u> ?
3. 3 x Negative 3 x minus three-fourths 4 y : 3x(-3x) - (3/4)4y; <u>-9x -3y</u> ?
4. one-fourth Negative 3 y minus three-fourths 7 y one-fourth minus 3 x:
(1/4)(-3y) - (3/4)7y - (1/4)(-3x); -(3/4)y -(21/4)y + (3/4)x; -(24/4)y + (3/4)x; ?
I don't see any of the answers as equivalent to <u>-3x - 2y, so please check my interpretations of the answer options.</u>
Might have to experiment a bit to choose the right answer.
In A, the first term is 456 and the common difference is 10. Each time we have a new term, the next one is the same except that 10 is added.
Suppose n were 1000. Then we'd have 456 + (1000)(10) = 10456
In B, the first term is 5 and the common ratio is 3. From 5 we get 15 by mult. 5 by 3. Similarly, from 135 we get 405 by mult. 135 by 3. This is a geom. series with first term 5 and common ratio 3. a_n = a_0*(3)^(n-1).
So if n were to reach 1000, the 1000th term would be 5*3^999, which is a very large number, certainly more than the 10456 you'd reach in A, above.
Can you now examine C and D in the same manner, and then choose the greatest final value? Safe to continue using n = 1000.
