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user100 [1]
3 years ago
9

Find the median for the following set of numbers: 100, 110, 120, 125, 140, 150, 160

Mathematics
2 answers:
Flauer [41]3 years ago
8 0
It would be 125.
best of luck!!
Serga [27]3 years ago
6 0

The median is the middle value in ur list. When the totals of the list are odd, the median is the middle entry in the list after sorting the list into increasing order. In this case, the total values in the list is odd 7, so the median is 125. Hope this helps

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Which expression is equivalent to<br> logbase12 ((1/2)/8w)?
Lunna [17]

\bf \begin{array}{llll} \textit{logarithm of factors} \\\\ log_a(xy)\implies log_a(x)+log_a(y) \end{array}~\hfill \begin{array}{llll} \textit{Logarithm of rationals} \\\\ log_a\left( \frac{x}{y}\right)\implies log_a(x)-log_a(y) \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \log_{12}\left( \cfrac{~~\frac{1}{2}~~}{8w} \right)\implies \begin{array}{llll} \log_{12}\left( \frac{1}{2} \right)&-&\log_{12}(8w)\\\\ \log_{12}(1)-\log_{12}(2)&-&[\log_{12}(8)+\log_{12}(w)] \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \log_{12}(1)-\log_{12}(2)-\log_{12}(8)-\log_{12}(w)~\hfill

7 0
3 years ago
A 50-foot flagpole is at the entrance of a building that is 300 feet tall. If the length of the flagpole's shadow is 30 feet at
Soloha48 [4]

The equation you can use to solve the problem is;

50/30 = 300/x

Next Cross Multiply

50x = 9000

x = 9000/50

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7 0
2 years ago
75% of n is 45. n is what percent of 90?​
Law Incorporation [45]

Answer:

66.67%

Step-by-step explanation:

75 /100 = .75

.75n = 45

45/.75 = 60

60 is n

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3 0
2 years ago
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You are jumping off the 12 foot diving board at the municipal pool. You bounce up at 6 feet per second and drop to the water you
NARA [144]

Answer:

When do you hit the water?

1.075 seconds after you jump.

What is your maximum height?

the maximum height is 12.5626 ft

Step-by-step explanation:

The equation:

h(t) = -16*t^2 + 6*t + 12

Is the height as a function of time.

We know that the initial height is the height when t = 0s

h(0s) = 12

and we know that the diving board is 12 foot tall.

Then the zero in h(t)

h(t) = 0

Represents the surface of the water.

When do you hit the water?

Here we just need to find the value of t such that:

h(t) = 0 = -16*t^2 + 6*t + 12

Using the Bhaskara's formula, we get:

t = \frac{-6 \pm \sqrt{6^2 - 4*(-16)*12} }{2*(-16)} = \frac{-6 \pm 28.4}{-32}

Then we have two solutions, and we only care for the positive solution (because the negative time happens before the jump, so that solution can be discarded)

The positive solution is:

t = (-6 - 28.4)/-32 = 1.075

So you hit the water 1.075 seconds after you jump.

What is your maximum height?

The height equation is a quadratic equation with a negative leading coefficient, then the maximum of this parabola is at the vertex.

We know that the vertex of a general quadratic:

a*x^2 + b*x + c

is at

x = -b/2a

Then in the case of our equation:

h(t) = -16*t^2 + 6*t + 12

The vertex is at:

t = -6/(2*-16) = 6/32 = 0.1875

Evaluating the height equation in that time will give us the maximum height, which is:

h(0.1875) =  -16*(0.1875 )^2 + 6*(0.1875) + 12 = 12.5626

And the height is in feet, then the maximum height is 12.5626 ft

6 0
3 years ago
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TiliK225 [7]
The answer is 1432 x 54 = 77,328
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3 years ago
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