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4 years ago

5

Define variables and write each phrase as an algebraic expression for ten more than Ruben

2 answers:

statuscvo [17]4 years ago

6 0

Variables are those unknowns which could have more than one value, and Algebraic expression is an expression that contains numbers, variables(EX, x and y) and Operations (EX,-, +).

maxonik [38]4 years ago

3 0

This is awfully general. Ruben has or does something. Whatever. Let's call that Whatever "r." Then the expression in question is "r+10."

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mel-nik [20]

Answer:

30

Step-by-step explanation:

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2 years ago

Which equation is the inverse of y = 2x^2 - 8?

evablogger [386]

Answer: A

Step-by-step explanation:

$y=2x^2-8$

1. Swap x and y.

$x=2y^2-8$

2. Solve for the new y.

Add 8

$x+8=2y^2$

Divide by 2.

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4 years ago

Circle P is described by the equation (x−1)2+(y+6)2=9 and circle Q is described by the equation (x+4)2+(y+14)2=4. Select from th

xeze [42]

Answer:

(a) Circle Q is 9.4 units to the center of circle P

(b) Circle Q has a smaller radius

Step-by-step explanation:

Given

$P:(x - 1)^2 + (y + 6)^2 = 9$

$Q:(x + 4)^2 + (y + 14)^2 = 4$

Solving (a): The distance between both

The equation of a circle is:

$(x - h)^2 + (y - k)^2 = r^2$

Where

$Center: (h,k)$

$Radius:r$

P and Q can be rewritten as:

$P:(x - 1)^2 + (y + 6)^2 = 3^2$

$Q:(x + 4)^2 + (y + 14)^2 = 2^2$

So, for P:

$Center = (1,-6)$

$r = 3$

For Q:

$Center = (-4,-14)$

$r = 2$

The distance between them is:

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2$

Where:

$Center = (1,-6)$ --- $(x_1,y_1)$

$Center = (-4,-14)$ --- $(x_2,y_2)$

So:

$d = \sqrt{(1 - -4)^2 + (-6 - -14)^2$

$d = \sqrt{(5)^2 + (8)^2$

$d = \sqrt{25 + 64$

$d = \sqrt{89$

$d = 9.4$

Solving (b): The radius;

In (a), we have:

$r = 3$ --- circle P

$r = 2$ --- circle Q

By comparison

$2 < 3$

<em>Hence, circle Q has a smaller radius</em>

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3 years ago

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3 years ago