You can easily test this if you know that (6, -10) corresponds to (X, Y). Knowing this, you can:
X = 6
Y = -10
you put this into your equation:
-10 = 3*6 - 8
calculate it:
-10 = 18 - 8
-10 = 10
This is not true of course, -10 is not equal to 10. Therefore, (6, -10) is not a solution of y = 3x-8 :)
Answer:
4
Step-by-step explanation:
The side length would be 4, but I'm a bit confused on what the "Recall the Formula" portion is about. I'm sorry if this doesn't help
the equation of a parabola in
vertex form
is.
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
∣
∣
∣
2
2
y
=
a
(
x
−
h
)
2
+
k
2
2
∣
∣
∣
−−−−−−−−−−−−−−−−−−−−−
where
(
h
,
k
)
are the coordinates of the vertex and a
is a multiplier
to obtain this form
complete the square
y
=
x
2
+
2
(
4
)
x
+
16
−
16
+
14
⇒
y
=
(
x
+
4
)
2
−
2
←
in vertex form
⇒
vertex
=
(
−
4
,
−
2
)
to obtain the intercepts
∙
let x = 0, in the equation for y-intercept
∙
let y = 0, in the equation for x-intercept
x
=
0
⇒
y
=
0
+
0
+
14
=
14
←
y-intercept
y
=
0
⇒
(
x
+
4
)
2
−
2
=
0
←
add 2 to both sides
⇒
(
x
+
4
)
2
=
2
take the square root of both sides
√
(
x
+
4
)
2
=
±
√
2
←
note plus or minus
⇒
x
+
4
=
±
√
2
←
subtract 4 from both sides
⇒
x
=
−
4
±
√
2
←
exact values
graph{(y-x^2-8x-14)((x+4)^2+(y+2)^2-0.04)=0 [-10, 10, -5, 5]}
Answer:
7.He borrowed $1853.33
8.She received $28990.936
Step-by-step explanation:
7.Let x be the amount borrowed by Tyson
Rate of interest = 7.5%
Time = 2.5 years
Simple Interest = 347.50
Formula : 
Where SI = simple interest
P = Principal
T = Time
R = Rate of interest
Substitute the values in the formula :

Hence he borrowed $1853.33
8) Principal = 20000
Rate of interest = 9.5%
No. of compounds per year = 2
Time = 4 years
Formula : 
Where A= amount
r = Rate of interest
n = no. of compounds
t = time
Substitute the values in the formula :
So, 
A=28990.936
Hence she received $28990.936
Answer:
see the attachments
Step-by-step explanation:
I suggested to you on a different occasion that by using tracing paper or tissue paper, you could make a copy of the image that you could move in the desired way to find its new location.
Here, the first attachment shows the figure being drawn on a piece of tissue with the line of reflection and the axes origin also shown.
The second attachment shows the tissue flopped over and the origin and line of reflection aligned with their previous locations. The new location of the figure is fairly obvious.
For <em>reflection</em>, any point that was some distance from the line on one side will be reflected to the same distance from the line on the other side. The distance is measured perpendicular to the line.
___
<em>Comment on "the work"</em>
I only have a badly focused image of your original worksheet to work from, but even that is sufficient to illustrate the process and the result. It took longer to make and edit the photos than to do the drawing necessary to find the answer.