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Nadusha1986 [10]
3 years ago
11

Determine which postulate or theorem can be used to prove that PQS ~=RQS

Mathematics
2 answers:
SVETLANKA909090 [29]3 years ago
7 0
The answer is B
SAS
Both triangles have congruent sides with an angle in between. 
emmainna [20.7K]3 years ago
4 0
The answer is B because both triangles have congruent sides with an angle in between. 

Hope my answer helped :)
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a colleague needs to move a 500 pound object that's on a lever. the fulcrum is 6 inches from the object. If your colleague weigh
Dafna11 [192]

Answer:

Step-by-step explanation:

The easier way to figure this is by using the concept of torque in physics. If the torque of the man is greater than that experienced by the box, the lever will tilt in the man's favor (in other words, he will move down and the box will be lifted). Torque is found by multiplying the perpendicular force by the length of the lever arm. Because we want the man's torque to be greater than the box's torque, the inequality is:

\tau_{man}>\tau_{box} and

180r>500(.1524) That decimal is 6 inches in terms of meters.

180r > 76.2 so

r > .42 meters or `16.67 inches. The man has to sit at a distance greater than 16.67 inches in order for the box to be lifted by the lever.

6 0
2 years ago
Aidan can complete a job in 5 minutes, while Joseph can complete the same job in 15
cluponka [151]

Answer:

10 minutes?

Step-by-step explanation:

Sorry if it is incorrect but what I did was I found the average of 5 minutes and 15 minutes and got 10.

Here's my problem solving explanation:

(5 + 15) / 2 = 10

3 0
3 years ago
Read 2 more answers
Janet has one rectangular-shaped paper with a length of 11/12 foot and a width of 3/4 foot.
Mice21 [21]
Hi bestie lol i’m failing math too and use this app as a lil cheat :)
5 0
2 years ago
NEED ASAP CORRECT ANSWER GETS BRAINLIESt
andriy [413]

Answer:

QS = 8x - 2

Step-by-step explanation:

QS = QR + RS

QS = 6x - 11 + 2x + 9

QS = 8x - 2

8 0
2 years ago
Find x<br><br><br><br><br> Thanks for the help in advance!
Marina86 [1]

I'm not sure if this is the easiest way of doing this, but it surely work.

Let the base of the triangle be AB, and let CH be the height. Just for reference, we have

AH=2,\quad HB=6,\quad AC=x

Moreover, let CH=y and BC=z

Now, AHC, CHB and ABC are all right triangles. If we write the pythagorean theorem for each of them, we have the following system

\begin{cases}4+y^2=x^2\\36+y^2=z^2\\x^2+z^2=64\end{cases}

If we solve the first two equations for y squared, we have

y^2=x^2-4\\y^2=z^2-36

And we can deduce

z^2 = x^2+32

So that the third equation becomes

x^2+x^2+32=64 \iff 2x^2 = 32 \iff x^2=16 \iff x=4

(we can't accept the negative root because negative lengths make no sense)

7 0
3 years ago
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