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3 years ago

Determine which postulate or theorem can be used to prove that PQS ~=RQS

Mathematics

2 answers:

SVETLANKA909090 [29]3 years ago

7 0

The answer is B
SAS
Both triangles have congruent sides with an angle in between.

emmainna [20.7K]3 years ago

4 0

The answer is B because both triangles have congruent sides with an angle in between.

Hope my answer helped :)

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Help ASAP!!!!!!!!!!!!!!!!!!!!!!

Fittoniya [83]

The answer would be +3 since ur adding 3 every time

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1 year ago

Read 2 more answers

Describe the transformation of g(x)=(-1/2x) as it relates to the graph of f(x)=x

sergiy2304 [10]

Answer:

Step-by-step explanation:

8 0

2 years ago

How many shapes did you put together to make 3/2

ella [17]

You put 3 shapes together I believe

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3 years ago

the temperature is already at 40 degrees it rises 4.5 degrees per minute how long will it take to get to 76 degrees

Andrei [34K]

Answer:

It will take 8 minutes for the temperature to reach 76°

Step-by-step explanation:

The expression for the total temperature in degrees at time t can be written as;

T=I+EM

where;

T=total temperature

I=initial temperature

E=temperature increase per minute

M=number of minutes

This can also be written as;

total temperature=initial temperature+temperature increase per minute×number of minutes

In our case;

T=76°

I=40°

E=4.5°

M=m

replacing;

76=40+(4.5×m)

4.5 m=76-40=36

(4.5 m)/4.5=36/4.5

m=8

It will take 8 minutes for the temperature to reach 76°

7 0

3 years ago

What is the area of the rectangle? shoe your work! do not round anything until the very end and round your final answer to the t

weeeeeb [17]

Answer:

The area of the rectangle is 42 units^2

Step-by-step explanation:

we know that

The area of rectangle is equal to

$A=LW$

In this problem

AB=DC

BC=AD

see the attached figure with letters to better understand the problem

we have that

$L=BC\\W=AB$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have the points

$A(2,-1),B(5,2),C(12,-5),D(9,-8)$

Find out the distance BC

we have

$B(5,2),C(12,-5)$

substitute in the formula

$d=\sqrt{(-5-2)^{2}+(12-5)^{2}}$

$d=\sqrt{(-7)^{2}+(7)^{2}}$

$d_B_C=\sqrt{98}\ units$

Find out the distance AB

we have

$A(2,-1),B(5,2)$

substitute in the formula

$d=\sqrt{(2+1)^{2}+(5-2)^{2}}$

$d=\sqrt{(3)^{2}+(3)^{2}}$

$d_A_B=\sqrt{18}\ units$

Find out the area

$A=(L)(W)$

we have

$L=d_B_C=\sqrt{98}\ units$

$W=d_A_B=\sqrt{18}\ units$

substitute

$A=(\sqrt{98})(\sqrt{18})=42.0\ units^2$

4 0

3 years ago