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Nadusha1986 [10]
3 years ago
11

Determine which postulate or theorem can be used to prove that PQS ~=RQS

Mathematics
2 answers:
SVETLANKA909090 [29]3 years ago
7 0
The answer is B
SAS
Both triangles have congruent sides with an angle in between. 
emmainna [20.7K]3 years ago
4 0
The answer is B because both triangles have congruent sides with an angle in between. 

Hope my answer helped :)
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Help ASAP!!!!!!!!!!!!!!!!!!!!!!
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The answer would be +3 since ur adding 3 every time
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Describe the transformation of g(x)=(-1/2x) as it relates to the graph of f(x)=x
sergiy2304 [10]

Answer:

c

Step-by-step explanation:

8 0
2 years ago
How many shapes did you put together to make 3/2
ella [17]
You put 3 shapes together I believe
5 0
3 years ago
the temperature is already at 40 degrees it rises 4.5 degrees per minute how long will it take to get to 76 degrees​
Andrei [34K]

Answer:

It will take 8 minutes for the temperature to reach 76°

Step-by-step explanation:

The expression for the total temperature in degrees at time t can be written as;

T=I+EM

where;

T=total temperature

I=initial temperature

E=temperature increase per minute

M=number of minutes

This can also be written as;

total temperature=initial temperature+temperature increase per minute×number of minutes

In our case;

T=76°

I=40°

E=4.5°

M=m

replacing;

76=40+(4.5×m)

4.5 m=76-40=36

(4.5 m)/4.5=36/4.5

m=8

It will take 8 minutes for the temperature to reach 76°

7 0
3 years ago
What is the area of the rectangle? shoe your work! do not round anything until the very end and round your final answer to the t
weeeeeb [17]

Answer:

The area of the rectangle is 42 units^2

Step-by-step explanation:

we know that

The area of rectangle is equal to

A=LW

In this problem

AB=DC

BC=AD

see the attached figure with letters to better understand the problem

we have that

L=BC\\W=AB

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have the points

A(2,-1),B(5,2),C(12,-5),D(9,-8)

<em>Find out the distance BC</em>

we have

B(5,2),C(12,-5)

substitute in the formula

d=\sqrt{(-5-2)^{2}+(12-5)^{2}}

d=\sqrt{(-7)^{2}+(7)^{2}}

d_B_C=\sqrt{98}\ units

<em>Find out the distance AB</em>

we have

A(2,-1),B(5,2)

substitute in the formula

d=\sqrt{(2+1)^{2}+(5-2)^{2}}

d=\sqrt{(3)^{2}+(3)^{2}}

d_A_B=\sqrt{18}\ units

<em>Find out the area</em>

A=(L)(W)

we have

L=d_B_C=\sqrt{98}\ units

W=d_A_B=\sqrt{18}\ units

substitute

A=(\sqrt{98})(\sqrt{18})=42.0\ units^2

4 0
3 years ago
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