Answer:
question 19
(2x-5)(3x+1)
Step-by-step explanation:
question 19
6x^2-13x-5
6x^2 coefficient = 6
-13x coeddicient = -13
-5 is constant
multiply coefficient of first term by the constant
i.e. 6*-5= -30
get 2 factors of -30 whoose sum equals -13
-15 +2 = -13
rewrite to have
6x^2-15x+2x-5
3x(2x-5) the firs term
1(2x-5)
add up,
(3x+1)(2x-5)
The numbers from which we are to determine the smallest number that can be divided leaving a remainder of 5 are 44, 55, and 220. We have to do the prime factorization of all the numbers to determine their least common multiple (LCM).
Factorization of 44:
44 = 11 x 4 = 11 x 2 x 2
Factorization of 55:
55 = 11 x 5
Factorization of 220:
220 = 11 x 20 = 11 x 5 x 4
Since 220 has all the factors from 55 and 44 then, the least common multiple is 220. Add 5 to the LCM in order to determine the unknown.
<em>ANSWER: 225</em>
Answer:
a)7x-3x
b)4+28y
Step-by-step explanation:
first one follow bidmas
2nd one just do 4 times 1 =4 and 7y times 4 equals 28y
You would multiply by
.
When you rationalize the denominator, you multiply by the conjugate of the denominator. The conjugate is the same numbers and radicals, but with the sign of the radical switched.
Answer:
give me the points its c c c c c c cc c cc c c. c cc cccc c cc c cc
