Solve using trigonometry. Round to the nearest degree. 16 х 30

Ms. Robinson gave her class 12 minutes to read. Carrie read 5 ½ pages in that time. At what rate, in pages per hour, did Carrie

9966 [12]

Answer:

27.5 pages read per hour

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Solve the system of equations. 12x - 5y = –20 y=x+4 2 = Y=

VARVARA [1.3K]

Answer:

Solution :

{x,y} = {0/14261512,4}

Step-by-step explanation:

Solve by Substitution :

// Solve equation [2] for the variable y

[2] y = x + 4

// Plug this in for variable y in equation [1]

[1] 12x - 5•(x +4) = -20

[1] 7x = 0

// Solve equation [1] for the variable x

[1] 7x = 0

[1] x = 0

// By now we know this much :

x = 0

y = x+4

// Use the x value to solve for y

y = (-0/14261512)+4 = 4

4 0

2 years ago

Read 2 more answers

Find the annual rate of interest. Principal = 4600 rupees, Period = 5 years, Total amount = 6440 rupees, Annual rate of interest

Len [333]

The annual rate of interest per year is 8%

Solution:

Given:- Principal (p) = 4600 rupees, Time –Period (t) = 5 years, Total amount(A) = 6440 rupees

First we will calculate the Interest and then using formula of simple interest we will calculate the rate of interest

Interest = Amount – Principal

Interest = 6440 – 4600 = 1840

Now using the formula of simple Interest and on putting values we get,

$\text {Simple Interest }=\frac{P \times R \times T}{100}$

Where "P" is the principal and "R" is the rate of interest per annum and "T" is the time period

$1840=\frac{4600 \times R \times 5}{100}$

$\begin{aligned} \mathrm{R} &=\frac{1840 \times 100}{4600 \times 5} \\\\ \mathrm{R} &=\frac{1840}{230} \\\\ \mathrm{R} &=8 \% \end{aligned}$

Hence, the required rate of interest per year is 8%

6 0

3 years ago

The question is in the picture. Plz helppp it is due tonight

Mkey [24]

Answer:

Step-by-step explanation:

We're given one equation, we have to find the other equation and solve each for 200, and whichever has the lower x is the winner

for Jayden we are given

$(0, 48), (1, 56), (2, 64), (3, 72), (4, 80)$

This looks to be a line. The y values are each separated by a common difference

We can use two points to describe the line

$m = \frac{y_2-y_1}{x_2-x_1} = \frac{80-48}{4-0} = \frac{32}{4} = 8\\ K = 8m + b\\48 = 8(0) + b\\b = 48\\so\\K = 8m + 48$

Now we can set both $K = 8m + 48$ and $K = m^2 + 10$ equal to 200

$200 = 8m + 48\\152 = 8m \\m = \frac{152}{8} = 19$

$200 = m^2 + 10\\m^2 = 190\\m = \sqrt{190} = 13.784$

Keiko's blog will reach 200 subscribers fastest.

7 0

2 years ago

What is the monthly payment on a 48-month loan for $28,000 with 2% interest?

GalinKa [24]

It’s b got it right on edge

8 0

1 year ago