Answer:
1/4
Step-by-step explanation:
rise: 1, run: 4
Answer:
Infinite pairs of numbers
1 and -1
8 and -8
Step-by-step explanation:
Let x³ and y³ be any two real numbers. If the sum of their cube roots is zero, then the following must be true:
![\sqrt[3]{x^3}+ \sqrt[3]{y^3}=0\\ \sqrt[3]{x^3}=- \sqrt[3]{y^3}\\x=-y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E3%7D%2B%20%5Csqrt%5B3%5D%7By%5E3%7D%3D0%5C%5C%20%5Csqrt%5B3%5D%7Bx%5E3%7D%3D-%20%5Csqrt%5B3%5D%7By%5E3%7D%5C%5Cx%3D-y)
Therefore, any pair of numbers with same absolute value but different signs fit the description, which means that there are infinite pairs of possible numbers.
Examples: 1 and -1; 8 and -8; 27 and -27.
Yes, this is correct. The tenths place is the first number to the right of the decimal. There is a 3 in that spot
To find if it rounds up or down, follow this rule.
Less than 5 round down and greater than 5 round up.
For this you look to the number next to it which is 7.
It rounds up so it is 9.4
Answer:
p=6.2
Step-by-step explanation:
I am going to have to say you will get an extra $1.50.
Hope this helped